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Chapter One: Vector Analysis The use of vectors and vector analysis ...

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Electromagnetic <strong>The</strong>orem<br />

(Dr. Omed Ghareb Abdullah) University <strong>of</strong> Sulaimani –College <strong>of</strong> Science – Physics Department<br />

<br />

v<br />

( <br />

E <br />

) dv <br />

first term<br />

<br />

2<br />

4 2<br />

<br />

0 0 0<br />

2<br />

4 2<br />

<br />

0 0 0<br />

second<br />

term <br />

third term<br />

<br />

(20 e<br />

20 e<br />

2<br />

4 2<br />

<br />

0 0 0<br />

2<br />

4 2<br />

<br />

0 0 0<br />

<br />

<br />

10 e<br />

<br />

10<br />

e<br />

<br />

2<br />

dd<br />

dz 80<br />

e<br />

<br />

3 d<br />

d<br />

dz<br />

d<br />

d<br />

dz 160<br />

e<br />

<br />

d<br />

<br />

2<br />

d<br />

2<br />

<br />

3 d<br />

d<br />

dz 24<br />

d<br />

24<br />

<br />

2<br />

2<br />

0<br />

2<br />

<br />

0<br />

2<br />

<br />

0<br />

by ( u dv)<br />

by ( u dv)<br />

2<br />

0<br />

48<br />

Example(5):<br />

Verify Stoke’s theorem for a <strong>vector</strong> field <br />

, in the segment <strong>of</strong> cylindrical surface<br />

defined by 2 , 60 90 , <strong>and</strong> 0 3 .<br />

<strong>The</strong> mathematical representation <strong>of</strong> Stokes’s theorem is given by:<br />

<br />

L<br />

<br />

A dl<br />

<br />

<br />

L<br />

<br />

A ds<br />

<strong>The</strong> line integral around a closed path defined by these bounded region is as follows:<br />

<br />

<br />

L<br />

b<br />

<br />

a<br />

c<br />

<br />

b<br />

d<br />

<br />

c<br />

a<br />

<br />

d<br />

<br />

B dl<br />

<br />

<br />

B dl<br />

<br />

<br />

B dl<br />

<br />

<br />

B dl<br />

<br />

<br />

B dl<br />

<br />

b<br />

<br />

a<br />

<br />

<br />

<br />

<br />

<br />

B dl<br />

<br />

B aˆ<br />

z<br />

z<br />

z<br />

z<br />

z<br />

B aˆ<br />

z<br />

B aˆ<br />

z<br />

B aˆ<br />

z<br />

c<br />

<br />

b<br />

<br />

d<br />

aˆ<br />

dz aˆ<br />

<br />

B dl<br />

<br />

z<br />

<br />

<br />

0<br />

<br />

d<br />

( aˆ<br />

) 0<br />

3<br />

<br />

0<br />

<br />

dz ( aˆ<br />

) <br />

z<br />

d<br />

c<br />

<br />

B dl<br />

<br />

cos<br />

cos90<br />

dz z<br />

2<br />

<br />

3<br />

<br />

0<br />

a<br />

<br />

d<br />

<br />

B dl<br />

0<br />

cos<br />

cos60<br />

dz z<br />

2<br />

3<br />

0<br />

3<br />

0<br />

3<br />

<br />

4<br />

ρ<br />

<strong>The</strong> left h<strong>and</strong> side <strong>of</strong> the Stokes’s theorem is :<br />

<br />

A <br />

<br />

s<br />

ds<br />

58

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