Chapter One: Vector Analysis The use of vectors and vector analysis ...
Chapter One: Vector Analysis The use of vectors and vector analysis ...
Chapter One: Vector Analysis The use of vectors and vector analysis ...
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Electromagnetic <strong>The</strong>orem<br />
(Dr. Omed Ghareb Abdullah) University <strong>of</strong> Sulaimani –College <strong>of</strong> Science – Physics Department<br />
<br />
v<br />
( <br />
E <br />
) dv <br />
first term<br />
<br />
2<br />
4 2<br />
<br />
0 0 0<br />
2<br />
4 2<br />
<br />
0 0 0<br />
second<br />
term <br />
third term<br />
<br />
(20 e<br />
20 e<br />
2<br />
4 2<br />
<br />
0 0 0<br />
2<br />
4 2<br />
<br />
0 0 0<br />
<br />
<br />
10 e<br />
<br />
10<br />
e<br />
<br />
2<br />
dd<br />
dz 80<br />
e<br />
<br />
3 d<br />
d<br />
dz<br />
d<br />
d<br />
dz 160<br />
e<br />
<br />
d<br />
<br />
2<br />
d<br />
2<br />
<br />
3 d<br />
d<br />
dz 24<br />
d<br />
24<br />
<br />
2<br />
2<br />
0<br />
2<br />
<br />
0<br />
2<br />
<br />
0<br />
by ( u dv)<br />
by ( u dv)<br />
2<br />
0<br />
48<br />
Example(5):<br />
Verify Stoke’s theorem for a <strong>vector</strong> field <br />
, in the segment <strong>of</strong> cylindrical surface<br />
defined by 2 , 60 90 , <strong>and</strong> 0 3 .<br />
<strong>The</strong> mathematical representation <strong>of</strong> Stokes’s theorem is given by:<br />
<br />
L<br />
<br />
A dl<br />
<br />
<br />
L<br />
<br />
A ds<br />
<strong>The</strong> line integral around a closed path defined by these bounded region is as follows:<br />
<br />
<br />
L<br />
b<br />
<br />
a<br />
c<br />
<br />
b<br />
d<br />
<br />
c<br />
a<br />
<br />
d<br />
<br />
B dl<br />
<br />
<br />
B dl<br />
<br />
<br />
B dl<br />
<br />
<br />
B dl<br />
<br />
<br />
B dl<br />
<br />
b<br />
<br />
a<br />
<br />
<br />
<br />
<br />
<br />
B dl<br />
<br />
B aˆ<br />
z<br />
z<br />
z<br />
z<br />
z<br />
B aˆ<br />
z<br />
B aˆ<br />
z<br />
B aˆ<br />
z<br />
c<br />
<br />
b<br />
<br />
d<br />
aˆ<br />
dz aˆ<br />
<br />
B dl<br />
<br />
z<br />
<br />
<br />
0<br />
<br />
d<br />
( aˆ<br />
) 0<br />
3<br />
<br />
0<br />
<br />
dz ( aˆ<br />
) <br />
z<br />
d<br />
c<br />
<br />
B dl<br />
<br />
cos<br />
cos90<br />
dz z<br />
2<br />
<br />
3<br />
<br />
0<br />
a<br />
<br />
d<br />
<br />
B dl<br />
0<br />
cos<br />
cos60<br />
dz z<br />
2<br />
3<br />
0<br />
3<br />
0<br />
3<br />
<br />
4<br />
ρ<br />
<strong>The</strong> left h<strong>and</strong> side <strong>of</strong> the Stokes’s theorem is :<br />
<br />
A <br />
<br />
s<br />
ds<br />
58