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Chapter One: Vector Analysis The use of vectors and vector analysis ...

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Electromagnetic <strong>The</strong>orem<br />

(Dr. Omed Ghareb Abdullah) University <strong>of</strong> Sulaimani –College <strong>of</strong> Science – Physics Department<br />

aˆ<br />

<br />

aˆ<br />

<br />

1 <br />

B <br />

<br />

<br />

0 0<br />

1<br />

B <br />

2<br />

<br />

<br />

cos<br />

aˆ<br />

<br />

aˆ<br />

z<br />

<br />

<br />

z<br />

cos<br />

<br />

sin<br />

aˆ<br />

<br />

<br />

1 <br />

aˆ<br />

<br />

<br />

<br />

<br />

sin<br />

( 0) aˆ<br />

<br />

<br />

cos<br />

(0 ) aˆ<br />

2<br />

<br />

z<br />

<br />

(0 0) <br />

<br />

Hence,<br />

<br />

s<br />

<br />

s<br />

<br />

s<br />

1<br />

( B)<br />

ds cos<br />

aˆ<br />

2<br />

s<br />

<br />

1<br />

( B)<br />

ds (cos)<br />

<br />

3 1<br />

( B)<br />

ds (0 ) <br />

2 2<br />

<br />

<br />

<br />

sin<br />

aˆ<br />

<br />

s<br />

<br />

<br />

dz d<br />

aˆ<br />

<br />

/ 2 3<br />

/ 3 0<br />

sin<br />

dz d<br />

2<br />

<br />

/ 2 3<br />

1<br />

( z)<br />

(cos<br />

/ 2 cos<br />

/ 3) (3 0)<br />

/ 3<br />

0 2<br />

3<br />

( B)<br />

ds <br />

4<br />

It is clearly seen that the left <strong>and</strong> right h<strong>and</strong> side has the same value, which indicates the<br />

validity <strong>of</strong> the Stokes’s theorem.<br />

<br />

<br />

Example (6):<br />

<br />

transform into spherical coordinate <strong>and</strong> find its magnitude at point 3, 4, 0.<br />

Solution:<br />

∙ ∙ ∙ ∙ <br />

∙ ∙ ∙ ∙ <br />

∙ ∙ ∙ ∙ <br />

<br />

∙ ∙ ∙ <br />

∙ ∙ ∙ <br />

∙ ∙ ∙ <br />

<br />

0 <br />

0 <br />

<br />

0 1 0 <br />

<br />

<br />

<br />

<br />

59

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