Chapter One: Vector Analysis The use of vectors and vector analysis ...
Chapter One: Vector Analysis The use of vectors and vector analysis ...
Chapter One: Vector Analysis The use of vectors and vector analysis ...
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Electromagnetic <strong>The</strong>orem<br />
(Dr. Omed Ghareb Abdullah) University <strong>of</strong> Sulaimani –College <strong>of</strong> Science – Physics Department<br />
OP (1 0) aˆ<br />
x<br />
( 3<br />
0) aˆ<br />
y<br />
(5 0) aˆ<br />
z<br />
aˆ<br />
(a).<br />
OR (0 0) aˆ<br />
(3 0) aˆ<br />
(8 0) aˆ<br />
3aˆ<br />
x<br />
y<br />
z<br />
x<br />
y<br />
3aˆ<br />
8aˆ<br />
z<br />
y<br />
5aˆ<br />
z<br />
(b). r <br />
QP<br />
( 1<br />
2) aˆ<br />
( 3<br />
4) aˆ<br />
(5 6) aˆ<br />
aˆ<br />
7 aˆ<br />
aˆ<br />
x<br />
y<br />
z<br />
x<br />
y<br />
z<br />
(c).<br />
2<br />
2<br />
2<br />
QR (0 2) (3 4) (8 6) 4 1<br />
4 3unit<br />
Example(12):<br />
Derive the cosine formula<br />
c<br />
2<br />
2 2<br />
a b 2abcos<br />
<strong>and</strong> the sine formula<br />
sin A sin B sin C<br />
using dot <strong>and</strong> cross product respectively.<br />
a b c<br />
b<br />
C<br />
Cosine formula:<br />
<br />
c a<br />
b<br />
<br />
c c (<br />
a b)<br />
(<br />
a b)<br />
a<br />
c<br />
2<br />
a<br />
2<br />
b<br />
2<br />
2<br />
b<br />
2<br />
A<br />
c<br />
2a<br />
b<br />
2 2<br />
2ab<br />
cos c a b 2abcos<br />
a<br />
B<br />
Sine formula:<br />
1 1 <br />
a b b c<br />
2 2<br />
<br />
1<br />
2<br />
a bsin<br />
c <br />
1<br />
2<br />
1 <br />
c a<br />
2<br />
b c sin a <br />
1<br />
2<br />
c a<br />
sin b<br />
dividing<br />
the above equation<br />
by<br />
( a b c ) we get :<br />
sin c<br />
c<br />
<br />
sin a<br />
a<br />
<br />
sin b<br />
b<br />
Example(13):<br />
<br />
<br />
Let E 3aˆ<br />
4aˆ<br />
<strong>and</strong> F 4aˆ<br />
10aˆ<br />
5aˆ<br />
, then find:<br />
x<br />
z<br />
x<br />
y<br />
z<br />
(a). the component <strong>of</strong><br />
E along<br />
F<br />
(b). A unit <strong>vector</strong> perpendicular to both<br />
E <strong>and</strong><br />
F<br />
Solution:<br />
(a). the <strong>vector</strong> component <strong>of</strong><br />
E along F is given by:<br />
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