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Chapter One: Vector Analysis The use of vectors and vector analysis ...

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Electromagnetic <strong>The</strong>orem<br />

(Dr. Omed Ghareb Abdullah) University <strong>of</strong> Sulaimani –College <strong>of</strong> Science – Physics Department<br />

<br />

. 27 <br />

<br />

. 27 1 3 1 4 1 5 7.65<br />

Example(8):<br />

Show that if the scalar function , is harmonic at point √3, ,0 .<br />

Solution:<br />

∂<br />

∂θ<br />

H 1 ∂<br />

r ∂r r sin θ e 1<br />

H 1 ∂ ∂H<br />

r r<br />

∂r ∂r 1<br />

r sinθ<br />

sinθ<br />

∂H<br />

∂θ 1<br />

∂ H<br />

r sin θ ∂φ <br />

∂<br />

r sinθ ∂θ sinθ2 sin θ cosθ e <br />

H sin θ<br />

r r e 2r e 2 e<br />

r sinθ sin θ 2sinθ cos θ <br />

H sin θ<br />

r<br />

e r2 2 e<br />

r 2 cos θ sin θ<br />

At point √3, ,0, H0 ⟹ is not harmonic.<br />

1<br />

r sin θ 0<br />

Example (9):<br />

Display whether the field <strong>vector</strong> is solenoid, conservative or none <strong>of</strong> them?<br />

Solution:<br />

(1). In order to show that the field is solenoid, it must be satisfy: ∙A 0<br />

∙A 1 r ∂ ∂r r A 1<br />

rsinθ<br />

<strong>The</strong>refore the field is not solenoid:<br />

∂<br />

∂θ sin θ A 1 ∂A <br />

rsinθ ∂φ<br />

∙A 1 r ∂ ∂r r 1 r r 3 0<br />

(2). In order to show that the field is conservative, it must be satisfy: A 0<br />

<br />

<br />

1<br />

<br />

<br />

1<br />

<br />

<br />

<br />

0 0<br />

1<br />

00 00 00 0<br />

<strong>The</strong>refore the field is conservative.<br />

61

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