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i. e. u 1z =βw 1x . Hence ( )<br />

u (0)<br />

1<br />

= 0 and as expected <strong>for</strong> shallow water flows u(0)<br />

z 1<br />

is<br />

independent from z:<br />

u (0)<br />

1<br />

= u (0) (x, t). (2.12)<br />

1<br />

We now correct this first order approximation. By using<br />

u 1 = u (0)<br />

1<br />

+βu (1)<br />

1<br />

+ O(β 2 ) (2.13)<br />

and Eq. (2.12) it is straight<strong>for</strong>ward that<br />

∫ 1<br />

η<br />

∫1<br />

u 2 1 dz=<br />

u 2 1 = u(0)<br />

2<br />

1 + 2βu<br />

(1)<br />

1 u(0) 1<br />

+ O(β 2 ),<br />

η<br />

u (0)<br />

1<br />

∫1<br />

2<br />

dz+2β<br />

η<br />

u (1)<br />

1 u(0) 1<br />

dz+O(β 2 ),<br />

and<br />

η 1 u 1· u 1 = u (0) 2<br />

1 (1−η)+2η1 βu (0)<br />

1 u(1) 1<br />

+ O(β 2 ),<br />

so that<br />

Also from Eq. (2.13),<br />

u 1· u 1 = u (0)<br />

1<br />

· u (0)<br />

1<br />

+ 2βu (0)<br />

1 u(1) 1<br />

+ O(β 2 ). (2.14)<br />

∫1<br />

1<br />

u 1 dz=u (0)<br />

1<br />

+βu (1)<br />

1<br />

+ O(β 2 ),<br />

η 1<br />

η<br />

u 1 = u (0)<br />

1<br />

+βu (1)<br />

1<br />

+ O(β 2 ),<br />

u 1· u 1 = u (0)<br />

1<br />

· u (0)<br />

1<br />

+ 2βu (0)<br />

1 u(1) 1<br />

+ O(β 2 ). (2.15)<br />

16

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