13.06.2015 Views

Approaches to Quantum Gravity

Approaches to Quantum Gravity

Approaches to Quantum Gravity

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

296 L. Freidel<br />

is now constrained <strong>to</strong> be in the conjugacy class of h me , where m e = 4πG ˜m e is the<br />

deficit angle created by the particle of mass ˜m e and h me is the element of the Cartan<br />

subgroup corresponding <strong>to</strong> the rotation of angle 2m e :<br />

( )<br />

e<br />

im<br />

0<br />

h m ≡<br />

0 e −im .<br />

The deficit angle is related <strong>to</strong> the parameter M e in the discrete action by<br />

κ M e = sin m e .<br />

Then the corresponding quantum amplitude<br />

∫ ∏ ∏ ∏ ∏ d 3 P e<br />

I (Ɣ) = dX e dg f dλ e<br />

4π e 1 ∑<br />

2<br />

2 e tr(X eG e )−iS PƔ (X e ,P e ,λ e )<br />

e<br />

f<br />

e∈Ɣ<br />

e∈Ɣ<br />

is given by<br />

∫ ∏<br />

I (Ɣ) =<br />

f<br />

dg f<br />

∏<br />

e∈Ɣ<br />

˜K me (G e ) ∏ e /∈Ɣ<br />

δ(G e ). (16.15)<br />

˜K m (g) is a function on SO(3) which is invariant under conjugation and defined in<br />

terms of the momenta 2iκ ⃗P(g) ≡ tr(g⃗σ) given by the projection of g on Pauli<br />

matrices.<br />

˜K m (g) =<br />

iκ 2<br />

(κ 2 P 2 (g) − sin 2 m − iɛ) . (16.16)<br />

Since this is a class function we can expand it in terms of characters. We have the<br />

identity<br />

˜K m (g) = ∑ K m ( j)χ j (g), (16.17)<br />

j∈N<br />

where χ j (h m ) is the character of h m in the j-representation:<br />

and<br />

χ j (h m ) =<br />

sin(2 j + 1)m<br />

,<br />

sin m<br />

K m ( j) = 2iκ2 e id j (m+iɛ)<br />

.<br />

cos m<br />

It is interesting <strong>to</strong> note that this is essentially the usual Feynman propaga<strong>to</strong>r evaluated<br />

on a discrete lattice, that is if k m (x) is the Feynamn propaga<strong>to</strong>r solution of<br />

(⊔⊓+m 2 )k m (x) =−iδ(x), then K m( j)<br />

d j<br />

= κ3 k m (κd j )<br />

cos m<br />

4π<br />

.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!