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Understanding Infrared Thermography Reading 7 Part 2 of 2.pdf

Understanding Infrared Thermography Reading 7 Part 2 of 2.pdf

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Thermal conductivity is analogous to electrical conductivity and is inversely<br />

proportional to thermal resistance, as shown in the lower portion <strong>of</strong> Figure A-1.<br />

The temperatures, T 1 and T 2 , are analogous to voltages V1 and V2, and the<br />

heat flow, Q/A, is analogous to electrical current, I, so that: if:<br />

R electrical = V1 - V2/ I<br />

then:<br />

R thermal<br />

= T1 - T2 / Q /A = L/K<br />

Heat flow is usually expressed in English units. K is expressed in<br />

BTU/hr∙ft²∙°F and thermal resistance (1/K) would then be expressed in<br />

°F∙hr∙ft²/BTU.<br />

Charlie Chong/ Fion Zhang

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