10.07.2015 Views

Thermodynamics

Thermodynamics

Thermodynamics

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

cen84959_ch03.qxd 4/1/05 12:31 PM Page 142142 | <strong>Thermodynamics</strong>REALGASasP 0 IDEALGASFIGURE 3–52At very low pressures, all gasesapproach ideal-gas behavior(regardless of their temperature).obtain the generalized compressibility chart that can be used for all gases(Fig. A–15).The following observations can be made from the generalized compressibilitychart:1. At very low pressures (P R 1), gases behave as an ideal gas regardlessof temperature (Fig. 3–52),2. At high temperatures (T R 2), ideal-gas behavior can be assumed withgood accuracy regardless of pressure (except when P R 1).3. The deviation of a gas from ideal-gas behavior is greatest in the vicinityof the critical point (Fig. 3–53).TNonideal-gasbehaviorIdeal-gasbehaviorEXAMPLE 3–11The Use of Generalized ChartsDetermine the specific volume of refrigerant-134a at 1 MPa and 50°C, using(a) the ideal-gas equation of state and (b) the generalized compressibilitychart. Compare the values obtained to the actual value of 0.021796 m 3 /kgand determine the error involved in each case.Ideal-gasbehaviorFIGURE 3–53Gases deviate from the ideal-gasbehavior the most in the neighborhoodof the critical point.vSolution The specific volume of refrigerant-134a is to be determinedassuming ideal- and nonideal-gas behavior.Analysis The gas constant, the critical pressure, and the critical temperatureof refrigerant-134a are determined from Table A–1 to be(a) The specific volume of refrigerant-134a under the ideal-gas assumptionisTherefore, treating the refrigerant-134a vapor as an ideal gas would result inan error of (0.026325 0.021796)/0.021796 0.208, or 20.8 percent inthis case.(b) To determine the correction factor Z from the compressibility chart, wefirst need to calculate the reduced pressure and temperature:ThusR 0.0815 kPa # m 3 >kg # KP cr 4.059 MPaT cr 374.2 Kv RTP 10.0815 kPa # m3 >kg # K21323 K2 0.026325 m 3 >kg1000 kPaP R P 1 MPaP cr 4.059 MPa 0.246T R T 323 K∂ Z 0.84T cr 374.2 K 0.863v Zv ideal 10.84210.026325 m 3 >kg2 0.022113 m 3 >kgDiscussion The error in this result is less than 2 percent. Therefore, in theabsence of tabulated data, the generalized compressibility chart can be usedwith confidence.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!