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Beginning and Intermediate Algebra - Wallace Math Courses ...

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LCD =(x + 3)(x − 3) Multiply each term by LCD<br />

(x − 3)(x + 3)(x − 3)<br />

+<br />

x + 3<br />

( − x − 3)(x+3)(x − 3)<br />

x − 3<br />

(x − 3)(x+3)(x − 3)<br />

+<br />

x+3<br />

(x + 3)(x + 3)(x − 3)<br />

x − 3<br />

(x − 3)(x − 3)+(−x − 3)(x + 3)<br />

(x − 3)(x − 3)+(x +3)(x + 3)<br />

x 2 − 6x +9−x 2 − 6x − 9<br />

x 2 − 6x + 9+x 2 +6x − 9<br />

− 12x<br />

2x 2 + 18<br />

− 12x<br />

2(x 2 + 9)<br />

− 6x<br />

x 2 − 9<br />

Reduce fractions<br />

FOIL<br />

Combine like terms<br />

Factor out 2 in denominator<br />

Divide out common factor2<br />

Our Solution<br />

If there are negative exponents in an expression we will have to first convert these<br />

negative exponents into fractions. Remember, the exponent is only on the factor<br />

it is attached to, not the whole term.<br />

Example 358.<br />

m −2 + 2m −1<br />

m +4m −2<br />

1<br />

m 2 + 2<br />

m<br />

m + 4<br />

m 2<br />

1(m2 )<br />

m2 + 2(m2 )<br />

m<br />

m(m2 )+ 4(m2 )<br />

m2 1 +2m<br />

m 3 + 4<br />

Make each negative exponent into a fraction<br />

Multiply each term by LCD,m 2<br />

Reduce the fractions<br />

Our Solution<br />

Once we convert each negative exponent into a fraction, the problem solves<br />

exactly like the other complex fraction problems.<br />

265

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