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Beginning and Intermediate Algebra - Wallace Math Courses ...

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x 4<br />

2 y 4<br />

6 · 2x 1<br />

2 y 5<br />

6<br />

x 7<br />

2y0 2x 5<br />

2 y 9<br />

6<br />

x 7<br />

2<br />

Example 416.<br />

⎛<br />

⎝<br />

⎛<br />

⎝ 25x1 3 y 2<br />

5<br />

9x 4<br />

5 y −3<br />

2<br />

25x 5<br />

15 y 4<br />

10<br />

9x 12 15<br />

−<br />

15 y 10<br />

Add exponents in numerator, in denominator, y 0 =1<br />

Subtract exponents onx, reduce exponent on y<br />

2x −1 y 3<br />

2 Negative exponent moves down to denominator<br />

2y 3<br />

2<br />

x<br />

⎞<br />

⎠<br />

⎞<br />

⎠<br />

− 1<br />

2<br />

− 1<br />

� 7<br />

−<br />

25x 15 y 19 � 1<br />

−<br />

2<br />

10<br />

9<br />

�<br />

9<br />

7<br />

−<br />

25x 15 y 19<br />

10<br />

9 1<br />

2<br />

Our Solution<br />

Using order of operations, simplify inside parenthesis first<br />

Need common denominators before we can subtract exponents<br />

2 Subtract exponents, be careful of the negative:<br />

4<br />

10 −<br />

�<br />

− 15<br />

�<br />

=<br />

10<br />

4 15 19<br />

+ =<br />

10 10 10<br />

�1<br />

2<br />

25 1 7<br />

−<br />

2 x 30 y 19<br />

20<br />

3x 7<br />

30<br />

5y 19<br />

20<br />

The negative exponent will flip the fraction<br />

The exponent 1<br />

goes on each factor<br />

2<br />

Evaluate 9 1<br />

2 <strong>and</strong> 25 1<br />

2 <strong>and</strong> move negative exponent<br />

Our Solution<br />

It is important to remember that as we simplify with rational exponents we are<br />

using the exact same properties we used when simplifying integer exponents. The<br />

only difference is we need to follow our rules for fractions as well. It may be worth<br />

reviewing your notes on exponent properties to be sure your comfortable with<br />

using the properties.<br />

312

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