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Evaluation of Septic Tank and Subsurface Wetland for

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Appendix 5 - BOD Sample Calculation<br />

Thiosulfate titrant volume is multiplied by 2 because the titrated sample is 100ml instead<br />

<strong>of</strong> st<strong>and</strong>ard method 200ml.<br />

Titration <strong>of</strong> sample on day one: 3.6ml thiosulfate x 2 = 7.2 mgO2/L<br />

Titration at end <strong>of</strong> five day incubation: 3.0ml x 2 = 6.0 mgO2/L<br />

7.2 – 6.0 = 1.2 mgO2/L depletion<br />

N = 300/(sample size in ml)<br />

For a dilution using a 10 ml sample: N = 300/10 = 30<br />

BOD = N x depletion = 30 x 1.2 = 36<br />

Theoretical BOD Temperature Correction<br />

Based Upon First Order Reaction Kinetics<br />

kT = reaction rate constant at temperature T<br />

k20 = reaction rate constant at 20C, assumed to be 0.23/day<br />

t = time in days<br />

UBOD = Ultimate Biochemical Oxygen Dem<strong>and</strong><br />

BOD5 = Five Day Biochemical Oxygen Dem<strong>and</strong> (BOD)<br />

BOD5 = UBOD (1 – e –kt )<br />

T-20<br />

k16 = k20θ<br />

Assuming �= 1.056<br />

θ<br />

k16 = 0.23 x 1.056 -4 = 0.185<br />

If BOD at 16C = 68<br />

68 = UBOD(1-e -0.185x5 )<br />

UBOD = 68 / (1-0.396) = 113<br />

BOD = UBOD (1 – e –kt )<br />

BOD at 20C = 113 (1 – e –0.23x5 ) = 77<br />

69

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