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DBI Analysis of Open String Bound States on Non-compact D-branes

DBI Analysis of Open String Bound States on Non-compact D-branes

DBI Analysis of Open String Bound States on Non-compact D-branes

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CHAPTER 2. BOSONIC STRINGS 32This gives us two equati<strong>on</strong>s relating the mode expansi<strong>on</strong>s <str<strong>on</strong>g>of</str<strong>on</strong>g> X − to those <str<strong>on</strong>g>of</str<strong>on</strong>g> the X i ’s, arelati<strong>on</strong> that can be solved explicity, and for the case <str<strong>on</strong>g>of</str<strong>on</strong>g> the open string the result is(αn − = 1 1l s p + 2D−2∑∞∑i=1 m=−∞: α i n−mα i m : −aδ n,0). (2.119)For the closed string, an analogous relati<strong>on</strong> for ˜α n − exists. Notice the ordering c<strong>on</strong>stanta again. The important point to note, is that now there are no independent oscillatorsleft for X − , so here again, we can no l<strong>on</strong>ger excite our string in the X − directi<strong>on</strong>! Thatis very good news indeed, because looking back at Eq. 2.56, and keeping in mind thatdue to our freshly introduced light-c<strong>on</strong>e coordinates our metric has somehow changed abit, 8 we now see that we are no l<strong>on</strong>ger able to create ghost states, even if we wanted todo so. In other words, the light-c<strong>on</strong>e gauge is manifestly free <str<strong>on</strong>g>of</str<strong>on</strong>g> ghost states.Let us now turn to the mass operator. The generic expressi<strong>on</strong> M 2 = −p µ p µ nowbecomesD−2∑M 2 = −p µ p µ = 2p + p − − p 2 i . (2.120)In order to work this out some more, let us focus <strong>on</strong> the case <str<strong>on</strong>g>of</str<strong>on</strong>g> open (Neumann) strings,and recall that in that caseα µ 0 = l sp µ .Hence, using p − = (l s ) −1 α0 − and Eq. 2.119, we compute that{ [(D−2∑D−2)2p + p − − p 2 i = 2p+ 1 ∑ ∑l s l s p + α−nα i ni + 1 2i=1i=1where we redefinedD−2∑− 1 ls2 i=1[(= 2 D−2 ∑ ∞∑ls2 i=1 n=1(αi0) 2,α i −nα i nn>0)− a],i=1D−2∑+∞∑i=1 n=−∞(αi0) 2]M 2 = 2 ls2 (N − a), (2.121)N =D−2∑i=1 n=1∞∑α−nα i n.iWe see that the mass-shell c<strong>on</strong>diti<strong>on</strong> in light-c<strong>on</strong>e gauge is identical to the <strong>on</strong>e in c<strong>on</strong>formalgauge (Eq. 2.104), except for the fact that we now simply have two directi<strong>on</strong>s lessin which we can excite our string. Hence, our groundstate still has α ′ M 2 |0〉 = −a|0〉.8 More specifically, we get g +− = g −+ = −1, and g ij = δ ij for i, j ∈ {1, . . . , D − 2}. But the tw<strong>on</strong>egatively valued entries corresp<strong>on</strong>d to directi<strong>on</strong>s in which we have no oscillators, and hence we can nol<strong>on</strong>ger create ghosts.− a}

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