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“mcs” — 2017/3/3 — 11:21 — page 147 — #155<br />

5.3. Strong Induction vs. Induction vs. Well Ordering 147<br />

Figure 5.12 S 0 ; S 1 ; S 2 and S 3 .<br />

Exam Problems<br />

Problem 5.14.<br />

Prove by induction that<br />

nX<br />

k kŠ D .n C 1/Š 1: (5.16)<br />

1<br />

Problem 5.15.<br />

Prove by induction:<br />

n.n C 1/ 2<br />

0 3 C 1 3 C 2 3 C C n 3 D<br />

; 8n 0:<br />

2<br />

using the equation itself as the induction hypothesis P.n/.<br />

(a) Prove the<br />

base case .n D 0/.<br />

(b) Now prove the<br />

inductive step.

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