TÀI LIỆU BỒI DƯỠNG HÓA HỌC 10 - CHƯƠNG 1-4 (CHƯƠNG TRÌNH CHUẨN) NĂM HỌC 2017-2018
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<strong>TÀI</strong> <strong>LIỆU</strong> <strong>BỒI</strong> <strong>DƯỠNG</strong>, NÂNG CAO <strong>HÓA</strong> <strong>HỌC</strong> <strong>10</strong><br />
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Produced by Nguyen Thanh Tu<br />
12) Cu + HNO 3loãng ⎯⎯→ Cu(NO 3 ) 2 + NO + H 2 O<br />
13) Fe 3 O 4 + HNO 3 (loãng) ⎯⎯→ Fe(NO 3 ) 3 + NO + H 2 O<br />
14) KMnO 4 + HCl (đặc) ⎯⎯→ KCl + MnCl 2 + Cl 2 + H 2 O<br />
15) KMnO 4 + SO 2 + H 2 O ⎯⎯→ K 2 SO 4 + MnSO 4 + H 2 SO 4<br />
t<br />
16) Mg + H 2 SO 0<br />
4(đặc)<br />
t<br />
17) Fe + H 2 SO 0<br />
4(đặc)<br />
⎯⎯→ MgSO 4 + H 2 S + H 2 O<br />
⎯⎯→ Fe 2 (SO 4 ) 3 + SO 2 + H 2 O<br />
18) NaNO 3 + Cu + H 2 SO 4 ⎯⎯→ CuSO 4 + Na 2 SO 4 + NO + H 2 O<br />
19) Al + NaNO 3 + NaOH + H 2 O ⎯⎯→ NaAlO 2 + NH 3<br />
t<br />
20) Fe 3 O 4 + H 2 SO 0<br />
4(đặc) ⎯⎯→ Fe 2 (SO 4 ) 3 + SO 2 + H 2 O<br />
Câu 2. Cân bằng các phản ứng sau đây theo phương pháp thăng bằng electron<br />
1) NaCrO 2 + NaOH + Cl 2 ⎯⎯→ Na 2 CrO 4 + NaCl + H 2 O<br />
2) K 2 Cr 2 O 7 + KI + H 2 SO 4 ⎯⎯→ Cr 2 (SO 4 ) 3 + I 2 + K 2 SO 4 + H 2 O<br />
3) KI + KClO 3 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + I 2 + KCl + H 2 O<br />
4) Al + HNO 3 (loãng) ⎯⎯→ Al(NO 3 ) 3 + NO + N 2 O + H 2 O (Biết tỉ lệ thể tích của NO và N 2 O là 1 : 3)<br />
5) FeS + HNO 3 (loãng) ⎯⎯→ Fe(NO 3 ) 3 + Fe 2 (SO 4 ) 3 + NO + H 2 O<br />
6) FeCl 2 + KMnO 4 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + MnSO 4 + Fe 2 (SO 4 ) 3 + Cl 2 + H 2 O<br />
7) CrI 3 + Cl 2 + KOH ⎯⎯→ K 2 CrO 4 + KIO 4 + KCl + H 2 O<br />
8) FeS 2 + HNO 3 + HCl ⎯⎯→ FeCl 3 + H 2 SO 4 + NO + H 2 O<br />
9) M x O y + HNO 3 ⎯⎯→ M(NO 3 ) n + NO + H 2 O<br />
t<br />
<strong>10</strong>) Fe x O y + HNO 0<br />
3(đặc)<br />
t<br />
11) Fe x O y + H 2 SO 0<br />
4(đặc)<br />
⎯⎯→ Fe(NO 3 ) 3 + NO 2 + H 2 O<br />
⎯⎯→ Fe 2 (SO 4 ) 3 + SO 2 + H 2 O<br />
12) Al + HNO 3 ⎯⎯→ Al(NO 3 ) 3 + N x O y + H 2 O<br />
13) CuFeS 2 + O 2 ⎯⎯→ CuO + Fe 2 O 3 + SO 2<br />
14) CuFeS 2 + Fe 2 (SO 4 ) 3 + O 2 + H 2 O ⎯⎯→ CuSO 4 + FeSO 4 + H 2 SO 4<br />
15) Fe 3 O 4 + HNO 3 ⎯⎯→ Fe(NO 3 ) 3 + N x O y + H 2 O<br />
16) Fe 2 O 3 + Al<br />
0<br />
t<br />
⎯⎯→ Fe n O m + Al 2 O 3<br />
17) Cr 2 O 3 + KNO 3 + KOH ⎯⎯→ K 2 CrO 4 + KNO 2 + H 2 O<br />
18) H x I y O z + H 2 S ⎯⎯→ I 2 + S + H 2 O<br />
19) Cr 2 S 3 + Mn(NO 3 ) 2 + K 2 CO 3 + HNO 3 ⎯⎯→ K 2 CrO 4 + K 2 SO 4 + K 2 MnO 4 + NO + CO 2 + H 2 O<br />
20) Fe(NO 3 ) 2 + KHSO 4 ⎯⎯→ Fe 2 (SO 4 ) 3 + Fe(NO 3 ) 3 + NO + H 2 O + K 2 SO 4<br />
21) FeSO 4 + KMnO 4 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + MnSO 4 + Fe 2 (SO 4 ) 3 + H 2 O<br />
22) FeSO 4 + KHSO 4 + KNO 3 ⎯⎯→ Fe 2 (SO 4 ) 3 + Fe(NO 3 ) 3 + K 2 SO 4 + NO + H 2 O<br />
23) NaNO 2 + KMnO 4 + KHSO 4 ⎯⎯→ NaNO 3 + MnSO 4 + K 2 SO 4 + H 2 O<br />
24) Fe x O y + HNO 3 ⎯⎯→ Fe(NO 3 ) 3 + NO + H 2 O<br />
25) KMnO 4 + H 2 S + KHSO 4 ⎯⎯→ MnSO 4 + K 2 SO 4 + S + H 2 O<br />
t<br />
26) CuFeS 2 + HNO 0<br />
3<br />
⎯⎯→ Cu(NO 3 ) 2 + Fe(NO 3 ) 3 + H 2 SO 4 + NO + H 2 O<br />
27) KI + KClO 3 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + I 2 + KCl + H 2 O<br />
28) Cu 2 S.FeS 2 + HNO 3 ⎯⎯→ Cu(NO 3 ) 2 + CuSO 4 + Fe 2 (SO 4 ) 3 + N 2 O + H 2 O<br />
29) KI + PbO 2 + HNO 3 ⎯⎯→ KNO 3 + I 2 + Pb(NO 3 ) 3 + H 2 O<br />
30) CuFeS 2 + HNO 3 (đặc) ⎯⎯→ Cu(NO 3 ) 2 + CuSO 4 + Fe 2 (SO 4 ) 3 + NO 2 + H 2 O<br />
<strong>BỒI</strong> <strong>DƯỠNG</strong> TOÁN - LÍ - <strong>HÓA</strong> CẤP 2+3 <strong>10</strong>00B TRẦN HƯNG ĐẠO TP.QUY NHƠN<br />
31) CrI 3 + Cl 2 + KOH ⎯⎯→ K 2 CrO 4 + KIO 4 + KCl + H 2 O<br />
32) K 2 Cr 2 O 7 + FeSO 4 + H 2 SO 4 ⎯⎯→ Cr 2 (SO 4 ) 3 + K 2 SO 4 + Fe 2 (SO 4 ) 3 + H 2 O<br />
33) Al + KNO 3 + KHSO 4 ⎯⎯→ Al(NO 3 ) 3 + Al 2 (SO 4 ) 3 + NO + K 2 SO 4 + H 2 O<br />
Sưu tầm bởi GV. Nguyễn Thanh Tú<br />
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