20.07.2017 Views

TÀI LIỆU BỒI DƯỠNG HÓA HỌC 10 - CHƯƠNG 1-4 (CHƯƠNG TRÌNH CHUẨN) NĂM HỌC 2017-2018

LINK DOCS.GOOGLE: https://drive.google.com/file/d/0B_NNtKpVZTUYWjJMeG1UaHNTb0U/view?usp=sharing

LINK DOCS.GOOGLE:
https://drive.google.com/file/d/0B_NNtKpVZTUYWjJMeG1UaHNTb0U/view?usp=sharing

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

www.twitter.com/daykemquynhon<br />

www.google.com/+DạyKèmQuyNhơn<br />

<strong>TÀI</strong> <strong>LIỆU</strong> <strong>BỒI</strong> <strong>DƯỠNG</strong>, NÂNG CAO <strong>HÓA</strong> <strong>HỌC</strong> <strong>10</strong><br />

www.facebook.com/daykem.quynhon<br />

www.daykemquynhon.blogspot.com<br />

www.daykemquynhon.ucoz.com<br />

Produced by Nguyen Thanh Tu<br />

12) Cu + HNO 3loãng ⎯⎯→ Cu(NO 3 ) 2 + NO + H 2 O<br />

13) Fe 3 O 4 + HNO 3 (loãng) ⎯⎯→ Fe(NO 3 ) 3 + NO + H 2 O<br />

14) KMnO 4 + HCl (đặc) ⎯⎯→ KCl + MnCl 2 + Cl 2 + H 2 O<br />

15) KMnO 4 + SO 2 + H 2 O ⎯⎯→ K 2 SO 4 + MnSO 4 + H 2 SO 4<br />

t<br />

16) Mg + H 2 SO 0<br />

4(đặc)<br />

t<br />

17) Fe + H 2 SO 0<br />

4(đặc)<br />

⎯⎯→ MgSO 4 + H 2 S + H 2 O<br />

⎯⎯→ Fe 2 (SO 4 ) 3 + SO 2 + H 2 O<br />

18) NaNO 3 + Cu + H 2 SO 4 ⎯⎯→ CuSO 4 + Na 2 SO 4 + NO + H 2 O<br />

19) Al + NaNO 3 + NaOH + H 2 O ⎯⎯→ NaAlO 2 + NH 3<br />

t<br />

20) Fe 3 O 4 + H 2 SO 0<br />

4(đặc) ⎯⎯→ Fe 2 (SO 4 ) 3 + SO 2 + H 2 O<br />

Câu 2. Cân bằng các phản ứng sau đây theo phương pháp thăng bằng electron<br />

1) NaCrO 2 + NaOH + Cl 2 ⎯⎯→ Na 2 CrO 4 + NaCl + H 2 O<br />

2) K 2 Cr 2 O 7 + KI + H 2 SO 4 ⎯⎯→ Cr 2 (SO 4 ) 3 + I 2 + K 2 SO 4 + H 2 O<br />

3) KI + KClO 3 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + I 2 + KCl + H 2 O<br />

4) Al + HNO 3 (loãng) ⎯⎯→ Al(NO 3 ) 3 + NO + N 2 O + H 2 O (Biết tỉ lệ thể tích của NO và N 2 O là 1 : 3)<br />

5) FeS + HNO 3 (loãng) ⎯⎯→ Fe(NO 3 ) 3 + Fe 2 (SO 4 ) 3 + NO + H 2 O<br />

6) FeCl 2 + KMnO 4 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + MnSO 4 + Fe 2 (SO 4 ) 3 + Cl 2 + H 2 O<br />

7) CrI 3 + Cl 2 + KOH ⎯⎯→ K 2 CrO 4 + KIO 4 + KCl + H 2 O<br />

8) FeS 2 + HNO 3 + HCl ⎯⎯→ FeCl 3 + H 2 SO 4 + NO + H 2 O<br />

9) M x O y + HNO 3 ⎯⎯→ M(NO 3 ) n + NO + H 2 O<br />

t<br />

<strong>10</strong>) Fe x O y + HNO 0<br />

3(đặc)<br />

t<br />

11) Fe x O y + H 2 SO 0<br />

4(đặc)<br />

⎯⎯→ Fe(NO 3 ) 3 + NO 2 + H 2 O<br />

⎯⎯→ Fe 2 (SO 4 ) 3 + SO 2 + H 2 O<br />

12) Al + HNO 3 ⎯⎯→ Al(NO 3 ) 3 + N x O y + H 2 O<br />

13) CuFeS 2 + O 2 ⎯⎯→ CuO + Fe 2 O 3 + SO 2<br />

14) CuFeS 2 + Fe 2 (SO 4 ) 3 + O 2 + H 2 O ⎯⎯→ CuSO 4 + FeSO 4 + H 2 SO 4<br />

15) Fe 3 O 4 + HNO 3 ⎯⎯→ Fe(NO 3 ) 3 + N x O y + H 2 O<br />

16) Fe 2 O 3 + Al<br />

0<br />

t<br />

⎯⎯→ Fe n O m + Al 2 O 3<br />

17) Cr 2 O 3 + KNO 3 + KOH ⎯⎯→ K 2 CrO 4 + KNO 2 + H 2 O<br />

18) H x I y O z + H 2 S ⎯⎯→ I 2 + S + H 2 O<br />

19) Cr 2 S 3 + Mn(NO 3 ) 2 + K 2 CO 3 + HNO 3 ⎯⎯→ K 2 CrO 4 + K 2 SO 4 + K 2 MnO 4 + NO + CO 2 + H 2 O<br />

20) Fe(NO 3 ) 2 + KHSO 4 ⎯⎯→ Fe 2 (SO 4 ) 3 + Fe(NO 3 ) 3 + NO + H 2 O + K 2 SO 4<br />

21) FeSO 4 + KMnO 4 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + MnSO 4 + Fe 2 (SO 4 ) 3 + H 2 O<br />

22) FeSO 4 + KHSO 4 + KNO 3 ⎯⎯→ Fe 2 (SO 4 ) 3 + Fe(NO 3 ) 3 + K 2 SO 4 + NO + H 2 O<br />

23) NaNO 2 + KMnO 4 + KHSO 4 ⎯⎯→ NaNO 3 + MnSO 4 + K 2 SO 4 + H 2 O<br />

24) Fe x O y + HNO 3 ⎯⎯→ Fe(NO 3 ) 3 + NO + H 2 O<br />

25) KMnO 4 + H 2 S + KHSO 4 ⎯⎯→ MnSO 4 + K 2 SO 4 + S + H 2 O<br />

t<br />

26) CuFeS 2 + HNO 0<br />

3<br />

⎯⎯→ Cu(NO 3 ) 2 + Fe(NO 3 ) 3 + H 2 SO 4 + NO + H 2 O<br />

27) KI + KClO 3 + H 2 SO 4 ⎯⎯→ K 2 SO 4 + I 2 + KCl + H 2 O<br />

28) Cu 2 S.FeS 2 + HNO 3 ⎯⎯→ Cu(NO 3 ) 2 + CuSO 4 + Fe 2 (SO 4 ) 3 + N 2 O + H 2 O<br />

29) KI + PbO 2 + HNO 3 ⎯⎯→ KNO 3 + I 2 + Pb(NO 3 ) 3 + H 2 O<br />

30) CuFeS 2 + HNO 3 (đặc) ⎯⎯→ Cu(NO 3 ) 2 + CuSO 4 + Fe 2 (SO 4 ) 3 + NO 2 + H 2 O<br />

<strong>BỒI</strong> <strong>DƯỠNG</strong> TOÁN - LÍ - <strong>HÓA</strong> CẤP 2+3 <strong>10</strong>00B TRẦN HƯNG ĐẠO TP.QUY NHƠN<br />

31) CrI 3 + Cl 2 + KOH ⎯⎯→ K 2 CrO 4 + KIO 4 + KCl + H 2 O<br />

32) K 2 Cr 2 O 7 + FeSO 4 + H 2 SO 4 ⎯⎯→ Cr 2 (SO 4 ) 3 + K 2 SO 4 + Fe 2 (SO 4 ) 3 + H 2 O<br />

33) Al + KNO 3 + KHSO 4 ⎯⎯→ Al(NO 3 ) 3 + Al 2 (SO 4 ) 3 + NO + K 2 SO 4 + H 2 O<br />

Sưu tầm bởi GV. Nguyễn Thanh Tú<br />

www.facebook.com/daykemquynhonofficial<br />

- 4 -<br />

www.facebook.com/boiduonghoahocquynhonofficial

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!