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<strong>Cosmic</strong> <strong>Game</strong> © Douglass A. White, 2012 v151207 210<br />

duodecimal (base 12) system except for time-keeping purposes. Other ancient cultures<br />

such as the Babylonians and Chinese also used duodecimal and/or sexagesimal (base 60)<br />

systems for tracking time, as we still do today. However, the Egyptians were special in<br />

their emphasis on the binary system, which they used widely in their standard weights<br />

and measures -- and which we in the conservative U.S. stubbornly continue to use in our<br />

liquid measures (gallon, half-gallon, quart, pint, cup, gill, half-gill, ounce, tablespoon).<br />

Feynman reviews the way in which a generalized system of logarithms is established. He<br />

uses base 10 for our ease in following the calculations. He creates the simple table of<br />

numbers that make up the "Successive Square Roots of Ten" chart that I transcribed on<br />

the previous page.<br />

I added some zeroes in front of numbers to keep the columns neat. Feynman points out<br />

that the value of 2.3025 actually is closer to 2.3026, but that is not critical to his<br />

discussion. <strong>The</strong> column on the left contains the <strong>com</strong>ponents of the Eye of Horus,<br />

carrying the series four more steps. <strong>The</strong> second column from the left simply inverts the<br />

first column and shows us the reciprocal of each <strong>com</strong>ponent of the Eye of Horus with<br />

respect to the arbitrary limit Feynman chose. He chose that limit because after ten steps<br />

the numbers in the third column be<strong>com</strong>e very close to unity, and they also converge on a<br />

fixed pattern that is also binary halving at each step, which means that we can then<br />

predict the whole continuing pattern in the same way we can predict the continuing series<br />

in the Benben pyramidion of the Great Pyramid. <strong>The</strong> column on the far right gives the<br />

difference between each succeeding entry in column four. After 26 the sum of all the<br />

other possible differences if we continue down the list is another 26, just like the sum of<br />

all the finer gradations of the Eye of Horus is 1/64, because the series be<strong>com</strong>es the same;<br />

each succeeding result is half the previous one. You can see this on your calculator if<br />

you pick any number and then start to hit the √ button over and over. <strong>The</strong> decimal<br />

portion after the 1 will start to be<strong>com</strong>e approximately 1/2 the previous value at each<br />

iteration, showing that the Eye of Horus is everywhere and sees all with its penetrating<br />

gaze. <strong>The</strong> 1 shows that, no matter how small the decimal fragment be<strong>com</strong>es, the Eye<br />

still gazes from Unity. <strong>The</strong> number 2.3025 be<strong>com</strong>es the key to establishing the natural<br />

logarithms on the base e = 2.7183, because e = 10 1/2.3025 = 10 0.434294 , where 0.434294 =<br />

444.72/1024. <strong>The</strong> interesting aspect of the "natural" base e is that loge (1 + n) ≈ n.<br />

That is e n = 1 + n as n → 0. <strong>The</strong> number 2.3025 <strong>com</strong>es from subtracting 26 from 51, the<br />

last digits of the last item in column four (2.3051), indicating we have taken the sequence<br />

to its Eye of Horus limit. <strong>The</strong> number 444.72 = 256 + 128 + 32 + 16 + 2 + 0.72, wherein<br />

the number .72 is below 1 and <strong>com</strong>es from knowing that by making ∆ small enough, we<br />

end up with 1 + 2.3025∆ for column three. So the final factor is 72% of 22511. <strong>The</strong><br />

decimal .0022486 below column three corresponds to the 2.3025 below column four and<br />

is almost equal to .0022511, allowing for the small remaining discrepancy before the<br />

sequence converges onto the Eye of Horus halving principle. So the final factor is 1 plus<br />

72% of .0022511 or 1.00162079. (Feynman uses .73 and gets 1.001643 as his final<br />

factor, which gives about the same result.) Look up the factors in the table and multiply<br />

all the factors to see if you get 2.7183 or something very close.

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