The Cosmic Game ( PDFDrive.com )

Cosmic Game © Douglass A. White, 2012 v151207 89
transcending the relative. At that moment the Tower disappears from within the Solar
Disk and becomes tangent to it. Symbolically this represents the meditation in which the
attention enters Samadhi and transcends the world of thought.
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The Horizon Towers as Two Mountains Framing the Solar Disk
The glyph of the sun at the horizon (aakhet)
reminded the Egyptions of the dawn and dusk meditation times.
We can select any point on the semicircle of the sun's arc through the sky to erect our
perpendicular obelisk gnomon that spiritually reaches up to touch that arc. When we
draw chords from its tip to the two horizons, the two chords will always be orthogonal to
each other. The two triangles they form with the horizon also will always be similar, and
thus the ratios for similar triangles always hold.
If we label the short hypotenuse A, the short diameter segment B, the obelisk C, the long
diameter segment D, and the long hypotenuse E, then we discover that A/C = E/D or AD
= CE. On the Senet Board example we set C = 1, so we get AD = E, which recapitulates
the product of the ratios of Planck's reduced constant ħ (pronounced h-bar) and the speed
of light. However, there are other ratios, such as B/C = C/D (i.e. BD = C 2 ). If we set C
to be 1 and let it stand for the speed of light, then we have the Einstein-de Broglie
Velocity Equation in which B represents a group velocity, C represents light speed, and D
represents the phase velocity that corresponds to B. The group velocity (vg) is always
less than or equal to light speed (c), and its corresponding phase velocity (vp) is always
greater than or equal to light speed. The Velocity Equation: (vg) (vp) = c 2 is thus an
example of a reciprocal relation.
If we choose a value such as .618 for B, then D becomes 1.618 and we have the Golden
Proportion. Of course we can set the Golden values for A, C, and E. If we let C = 1 and
D = 2, then E becomes √5 and we have a Golden Triangle, and A becomes .5√5.
It appears that the values we derive from the Senet Board are scale independent, since we
find that analogs to light speed and Planck's constant occur at the same scale in the
geometry of triangles inscribed in circles when held by the Senet Board grid.
In our formula (ħ c) = (1.054e-34 J·s) (3e8 m/s) = 3.1623e-26 J·m we can convert the
expression into units of space and time. Energy (J) is inverse velocity (according to
Larson), so we discover from Larson's viewpoint that the product of Planck's constant
and the speed of light is actually a very small quantum unit of time (t). Substituting into
our similar triangle ratios, we discover that A is in units of t 2 /s, D is in units of s/t, E is in
units of s, and therefore, C must be in units of energy (t/s). We find that B must be in
terms of mass (t/s) 3 .