06.09.2021 Views

Fundamentals of Matrix Algebra, 2011a

Fundamentals of Matrix Algebra, 2011a

Fundamentals of Matrix Algebra, 2011a

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Chapter 2<br />

<strong>Matrix</strong> Arithmec<br />

4. T/F: If A is inverble, then A⃗x = ⃗0 has exactly 1 soluon.<br />

5. What is a corollary?<br />

6. Fill in the blanks: a matrix is inverble is useful; compung the inverse<br />

is .<br />

Once again we visit the old algebra equaon, ax = b. How do we solve for x? We<br />

know that, as long as a ≠ 0,<br />

x = b a , or, stated in another way, x = a−1 b.<br />

What is a −1 ? It is the number that, when mulplied by a, returns 1. That is,<br />

a −1 a = 1.<br />

Let us now think in terms <strong>of</strong> matrices. We have learned <strong>of</strong> the identy matrix I that<br />

“acts like the number 1.” That is, if A is a square matrix, then<br />

IA = AI = A.<br />

If we had a matrix, which we’ll call A −1 , where A −1 A = I, then by analogy to our algebra<br />

example above it seems like we might be able to solve the linear system A⃗x = ⃗b for ⃗x<br />

by mulplying both sides <strong>of</strong> the equaon by A −1 . That is, perhaps<br />

⃗x = A −1 ⃗b.<br />

Of course, there is a lot <strong>of</strong> speculaon here. We don’t know that such a matrix like<br />

A −1 exists. However, we do know how to solve the matrix equaon AX = B, so we<br />

can use that technique to solve the equaon AX = I for X. This seems like it will get us<br />

close to what we want. Let’s pracce this once and then study our results.<br />

. Example 53 .Let<br />

Find a matrix X such that AX = I.<br />

A =<br />

[ ] 2 1<br />

.<br />

1 1<br />

S We know how to solve this from the previous secon: we form<br />

the proper augmented matrix, put it into reduced row echelon form and interpret the<br />

results. [ ] [ ]<br />

2 1 1 0 −→ 1 0 1 −1<br />

rref<br />

1 1 0 1<br />

0 1 −1 2<br />

We read from our matrix that<br />

X =<br />

[ ] 1 −1<br />

.<br />

−1 2<br />

104

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!