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Fundamentals of Matrix Algebra, 2011a

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5.3 Visualizing Vectors: Vectors in Three Dimensions<br />

It is easy to compute<br />

⎡ ⎤<br />

2<br />

2⃗v = ⎣ 4 ⎦ and<br />

⎡ ⎤<br />

−1<br />

−⃗v = ⎣ −2 ⎦ .<br />

6<br />

−3<br />

These are drawn in Figure 5.23. This figure is, in many ways, a mess, with all the<br />

dashed and doed lines. They are useful though. Use them to see how each vector<br />

was formed, and note that 2⃗v at least looks twice as long as ⃗v, and it looks like −⃗v<br />

points in the opposite direcon. 20 .<br />

Vector Length<br />

How do we measure the length <strong>of</strong> a vector in 3D? In 2D, we were able to answer this<br />

queson by using the Pythagorean Theorem. Does the Pythagorean Theorem apply in<br />

3D? In a sense, it does. ⎡ ⎤<br />

Consider the vector ⃗v = ⎣ 1 2 ⎦, as drawn in Figure 5.24 (a), with guiding dashed<br />

3<br />

lines. Now look at part (b) <strong>of</strong> the same figure. Note how two lengths <strong>of</strong> the dashed<br />

lines have now been drawn gray, and another doed line has been added.<br />

z<br />

z<br />

.<br />

y<br />

y<br />

x<br />

(a)<br />

x<br />

(b)<br />

.<br />

Figure 5.24: Compung the length <strong>of</strong> ⃗v<br />

These gray dashed and doed lines form a right triangle with the doed line forming<br />

the hypotenuse. We can find the length <strong>of</strong> the doed line using the Pythagorean<br />

Theorem.<br />

length <strong>of</strong> the doed line = √ sum <strong>of</strong> the squares <strong>of</strong> the dashed line lengths<br />

That is, the length <strong>of</strong> the doed line = √ 1 2 + 2 2 = √ 5.<br />

20 Our previous work showed that looks can be deceiving, but it is indeed true in this case.<br />

223

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