06.09.2021 Views

Fundamentals of Matrix Algebra, 2011a

Fundamentals of Matrix Algebra, 2011a

Fundamentals of Matrix Algebra, 2011a

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

5.2 Properes <strong>of</strong> Linear Transformaons<br />

leads us to an important theorem. The first part we have essenally just proved; the<br />

second part we won’t prove, although its truth is very powerful.<br />

.<br />

Ṫheorem 21<br />

Matrices and Linear Transformaons<br />

.<br />

1. Define T : R n → R m by T(⃗x) = A⃗x, where A is an<br />

m × n matrix. Then T is a linear transformaon.<br />

2. Let T : R n → R m be any linear transformaon. Then<br />

there exists an unique m×n matrix A such that T(⃗x) =<br />

A⃗x.<br />

The second part <strong>of</strong> the theorem says that all linear transformaons can be described<br />

using matrix mulplicaon. Given any linear transformaon, there is a matrix<br />

that completely defines that transformaon. This important matrix gets its own name.<br />

.<br />

Ḋefinion 30<br />

Standard <strong>Matrix</strong> <strong>of</strong> a Linear Transformaon<br />

.<br />

Let T : R n → R m be a linear transformaon. By Theorem<br />

21, there is a matrix A such that T(⃗x) = A⃗x. This matrix A<br />

is called the standard matrix <strong>of</strong> the linear transformaon T,<br />

and is denoted [ T ]. a<br />

a The matrix–like brackets around T suggest that the standard matrix A<br />

is a matrix “with T inside.”<br />

While exploring all <strong>of</strong> the ramificaons <strong>of</strong> Theorem 21 is outside the scope <strong>of</strong> this<br />

text, let it suffice to say that since 1) linear transformaons are very, very important<br />

in economics, science, engineering and mathemacs, and 2) the theory <strong>of</strong> matrices is<br />

well developed and easy to implement by hand and on computers, then 3) it is great<br />

news that these two concepts go hand in hand.<br />

We have already used the second part <strong>of</strong> this theorem in a small way. In the previous<br />

secon we looked at transformaons graphically and found the matrices that<br />

produced them. At the me, we didn’t realize that these transformaons were linear,<br />

but indeed they were.<br />

This brings us back to the movang example with which we started this secon.<br />

We tried to find the matrix that translated the unit square one unit to the right. Our<br />

aempt failed, and we have yet to determine why. Given our link between matrices<br />

and linear transformaons, the answer is likely “the translaon transformaon is not<br />

a linear transformaon.” While that is a true statement, it doesn’t really explain things<br />

all that well. Is there some way we could have recognized that this transformaon<br />

207

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!