Fundamentals of Matrix Algebra, 2011a
Fundamentals of Matrix Algebra, 2011a
Fundamentals of Matrix Algebra, 2011a
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Chapter 3<br />
Operaons on Matrices<br />
S To compute the minor A 1,3 , we remove the first row and third column<br />
<strong>of</strong> A then take the determinant.<br />
⎡<br />
A = ⎣ 1 2 3 ⎤ ⎡<br />
4 5 6 ⎦ ⇒ ⎣ 1 2 3 ⎤<br />
[ ]<br />
4 5 6 ⎦ 4 5<br />
⇒<br />
7 8<br />
7 8 9 7 8 9<br />
A 1,3 =<br />
∣ 4 5<br />
7 8 ∣ = 32 − 35 = −3.<br />
The corresponding c<strong>of</strong>actor, C 1,3 , is<br />
C 1,3 = (−1) 1+3 A 1,3 = (−1) 4 (−3) = −3.<br />
The minor A 3,2 is found by removing the third row and second column <strong>of</strong> A then<br />
taking the determinant.<br />
⎡<br />
A = ⎣ 1 2 3 ⎤ ⎡<br />
4 5 6 ⎦ ⇒ ⎣ 1 2 3 ⎤<br />
[ ]<br />
4 5 6 ⎦ 1 3<br />
⇒<br />
4 6<br />
7 8 9 7 8 9<br />
A 3,2 =<br />
∣ 1 3<br />
4 6 ∣ = 6 − 12 = −6.<br />
The corresponding c<strong>of</strong>actor, C 3,2 , is<br />
C 3,2 = (−1) 3+2 A 3,2 = (−1) 5 (−6) = 6.<br />
.<br />
The minor B 2,1 is found by removing the second row and first column <strong>of</strong> B then<br />
taking the determinant.<br />
⎡<br />
⎤ ⎡<br />
⎤<br />
1 2 0 8 1 2 0 8 ⎡<br />
B = ⎢ −3 5 7 2<br />
⎥<br />
⎣ −1 9 −4 6 ⎦ ⇒ ⎢ -3 5 7 2<br />
⎥<br />
⎣ -1 9 −4 6 ⎦ ⇒ ⎣ 2 0 8 ⎤<br />
9 −4 6 ⎦<br />
1 1 1<br />
1 1 1 1 1 1 1 1<br />
2 0 8<br />
B 2,1 =<br />
9 −4 6<br />
!<br />
= ?<br />
∣ 1 1 1 ∣<br />
We’re a bit stuck. We don’t know how to find the determinate <strong>of</strong> this 3 × 3 matrix.<br />
We’ll come back to this later. The corresponding c<strong>of</strong>actor is<br />
C 2,1 = (−1) 2+1 B 2,1 = −B 2,1 ,<br />
whatever this number happens to be.<br />
The minor B 4,3 is found by removing the fourth row and third column <strong>of</strong> B then<br />
taking the determinant.<br />
⎡<br />
⎤ ⎡<br />
⎤<br />
1 2 0 8 1 2 0 8 ⎡<br />
B = ⎢ −3 5 7 2<br />
⎥<br />
⎣ −1 9 −4 6 ⎦ ⇒ ⎢ −3 5 7 2<br />
⎥<br />
⎣ −1 9 -4 6 ⎦ ⇒ ⎣ 1 2 8 ⎤<br />
−3 5 2 ⎦<br />
−1 9 6<br />
1 1 1 1 1 1 1 1<br />
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