06.09.2021 Views

Fundamentals of Matrix Algebra, 2011a

Fundamentals of Matrix Algebra, 2011a

Fundamentals of Matrix Algebra, 2011a

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Chapter 3<br />

Operaons on Matrices<br />

S To compute the minor A 1,3 , we remove the first row and third column<br />

<strong>of</strong> A then take the determinant.<br />

⎡<br />

A = ⎣ 1 2 3 ⎤ ⎡<br />

4 5 6 ⎦ ⇒ ⎣ 1 2 3 ⎤<br />

[ ]<br />

4 5 6 ⎦ 4 5<br />

⇒<br />

7 8<br />

7 8 9 7 8 9<br />

A 1,3 =<br />

∣ 4 5<br />

7 8 ∣ = 32 − 35 = −3.<br />

The corresponding c<strong>of</strong>actor, C 1,3 , is<br />

C 1,3 = (−1) 1+3 A 1,3 = (−1) 4 (−3) = −3.<br />

The minor A 3,2 is found by removing the third row and second column <strong>of</strong> A then<br />

taking the determinant.<br />

⎡<br />

A = ⎣ 1 2 3 ⎤ ⎡<br />

4 5 6 ⎦ ⇒ ⎣ 1 2 3 ⎤<br />

[ ]<br />

4 5 6 ⎦ 1 3<br />

⇒<br />

4 6<br />

7 8 9 7 8 9<br />

A 3,2 =<br />

∣ 1 3<br />

4 6 ∣ = 6 − 12 = −6.<br />

The corresponding c<strong>of</strong>actor, C 3,2 , is<br />

C 3,2 = (−1) 3+2 A 3,2 = (−1) 5 (−6) = 6.<br />

.<br />

The minor B 2,1 is found by removing the second row and first column <strong>of</strong> B then<br />

taking the determinant.<br />

⎡<br />

⎤ ⎡<br />

⎤<br />

1 2 0 8 1 2 0 8 ⎡<br />

B = ⎢ −3 5 7 2<br />

⎥<br />

⎣ −1 9 −4 6 ⎦ ⇒ ⎢ -3 5 7 2<br />

⎥<br />

⎣ -1 9 −4 6 ⎦ ⇒ ⎣ 2 0 8 ⎤<br />

9 −4 6 ⎦<br />

1 1 1<br />

1 1 1 1 1 1 1 1<br />

2 0 8<br />

B 2,1 =<br />

9 −4 6<br />

!<br />

= ?<br />

∣ 1 1 1 ∣<br />

We’re a bit stuck. We don’t know how to find the determinate <strong>of</strong> this 3 × 3 matrix.<br />

We’ll come back to this later. The corresponding c<strong>of</strong>actor is<br />

C 2,1 = (−1) 2+1 B 2,1 = −B 2,1 ,<br />

whatever this number happens to be.<br />

The minor B 4,3 is found by removing the fourth row and third column <strong>of</strong> B then<br />

taking the determinant.<br />

⎡<br />

⎤ ⎡<br />

⎤<br />

1 2 0 8 1 2 0 8 ⎡<br />

B = ⎢ −3 5 7 2<br />

⎥<br />

⎣ −1 9 −4 6 ⎦ ⇒ ⎢ −3 5 7 2<br />

⎥<br />

⎣ −1 9 -4 6 ⎦ ⇒ ⎣ 1 2 8 ⎤<br />

−3 5 2 ⎦<br />

−1 9 6<br />

1 1 1 1 1 1 1 1<br />

138

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!