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Fundamentals of Matrix Algebra, 2011a

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Chapter 4<br />

Eigenvalues and Eigenvectors<br />

.<br />

Ḋefinion 28<br />

Characterisc Polynomial<br />

.<br />

Let A be an n × n matrix. The characterisc polynomial <strong>of</strong> A<br />

is the n th degree polynomial p(λ) = det (A − λI).<br />

Our definion just states what the characterisc polynomial is. We know from our<br />

work so far why we care: the roots <strong>of</strong> the characterisc polynomial <strong>of</strong> an n × n matrix<br />

A are the eigenvalues <strong>of</strong> A.<br />

In Examples 84 and 85, we found eigenvalues and eigenvectors, respecvely, <strong>of</strong><br />

a given matrix. That is, given a matrix A, we found values λ and vectors ⃗x such that<br />

A⃗x = λ⃗x. The steps that follow outline the general procedure for finding eigenvalues<br />

and eigenvectors; we’ll follow this up with some examples.<br />

.<br />

Finding Eigenvalues and Eigenvectors<br />

. Key Idea 14<br />

Let A be an n × n matrix.<br />

1. To find the eigenvalues.<br />

<strong>of</strong> A, compute p(λ), the characterisc<br />

polynomial <strong>of</strong> A, set it equal to 0, then solve<br />

for λ.<br />

2. To find the eigenvectors <strong>of</strong> A, for each eigenvalue<br />

solve the homogeneous system (A − λI)⃗x = ⃗0.<br />

. Example 86 .Find the eigenvalues <strong>of</strong> A, and for each eigenvalue, find an eigenvector<br />

where<br />

[ ] −3 15<br />

A =<br />

.<br />

3 9<br />

S<br />

equal to 0.<br />

To find the eigenvalues, we must compute det (A − λI) and set it<br />

det (A − λI) =<br />

∣<br />

−3 − λ 15<br />

3 9 − λ<br />

∣<br />

= (−3 − λ)(9 − λ) − 45<br />

= λ 2 − 6λ − 27 − 45<br />

= λ 2 − 6λ − 72<br />

= (λ − 12)(λ + 6)<br />

Therefore, det (A − λI) = 0 when λ = −6 and 12; these are our eigenvalues. (We<br />

168

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