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Fundamentals of Matrix Algebra, 2011a

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Chapter 2<br />

<strong>Matrix</strong> Arithmec<br />

.<br />

Ṫheorem 8<br />

Inverble Matrices and Soluons to A⃗x = ⃗b<br />

.<br />

Let A be an inverble n × n matrix, and let ⃗b be any n × 1<br />

column vector. Then the equaon A⃗x = ⃗b has exactly one<br />

soluon, namely<br />

⃗x = A −1 ⃗b.<br />

A corollary 19 to this theorem is: If A is not inverble, then A⃗x = ⃗b does not have<br />

exactly one soluon. It may have infinite soluons and it may have no soluon, and<br />

we would need to examine the reduced row echelon form <strong>of</strong> the augmented matrix<br />

[<br />

A ⃗b ] to see which case applies.<br />

We demonstrate our theorem with an example.<br />

. Example 57 Solve A⃗x = ⃗b by compung ⃗x = A −1 ⃗b, where<br />

⎡<br />

A = ⎣ 1 0 −3 ⎤ ⎡<br />

−3 −4 10 ⎦ and ⃗b = ⎣ −15 ⎤<br />

57 ⎦ .<br />

4 −5 −11<br />

−46<br />

S<br />

Without showing our steps, we compute<br />

⎡<br />

⎤<br />

94 15 −12<br />

A −1 = ⎣ 7 1 −1 ⎦ .<br />

31 5 −4<br />

We then find the soluon to A⃗x = ⃗b by compung A −1 ⃗b:<br />

⃗x = A −1 ⃗b<br />

⎡<br />

94 15 −12<br />

= ⎣ 7 1 −1<br />

31 5 −4<br />

⎡<br />

= ⎣ −3 ⎤<br />

−2 ⎦ .<br />

4<br />

⎤ ⎡<br />

⎦<br />

⎣ −15<br />

57<br />

−46<br />

⎤<br />

⎦<br />

.<br />

We can easily check our answer:<br />

⎡<br />

⎣ −3 −4 10<br />

1 0 −3<br />

4 −5 −11<br />

⎤ ⎡<br />

⎦ ⎣ −3 ⎤ ⎡<br />

−2 ⎦ = ⎣ −15 ⎤<br />

57 ⎦ .<br />

4 −46<br />

19 a corollary is an idea that follows directly from a theorem<br />

110

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