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Fundamentals of Matrix Algebra, 2011a

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Chapter 2<br />

<strong>Matrix</strong> Arithmec<br />

BB = BC, yet B ≠ C. In general, just because AX = BX, we cannot conclude that A = B.<br />

<strong>Matrix</strong> mulplicaon is turning out to be a very strange operaon. We are very<br />

used to mulplying numbers, and we know a bunch <strong>of</strong> properes that hold when using<br />

this type <strong>of</strong> mulplicaon. When mulplying matrices, though, we probably find ourselves<br />

asking two quesons, “What does work?” and “What doesn’t work?” We’ll answer<br />

these quesons; first we’ll do an example that demonstrates some <strong>of</strong> the things<br />

that do work.<br />

. Example 30 .Let<br />

A =<br />

[ ] [ ]<br />

1 2 1 1<br />

, B =<br />

3 4 1 −1<br />

and C =<br />

[ ] 2 1<br />

.<br />

1 2<br />

Find the following:<br />

1. A(B + C)<br />

2. AB + AC<br />

3. A(BC)<br />

4. (AB)C<br />

S We’ll compute each <strong>of</strong> these without showing all the intermediate<br />

steps. Keep in mind order <strong>of</strong> operaons: things that appear inside <strong>of</strong> parentheses<br />

are computed first.<br />

1.<br />

[ ] ([ 1 2 1 1<br />

A(B + C) =<br />

3 4 1 −1<br />

[ ] [ ]<br />

1 2 3 2<br />

=<br />

3 4 2 1<br />

[ ] 7 4<br />

=<br />

17 10<br />

]<br />

+<br />

[ ]) 2 1<br />

1 2<br />

2.<br />

[ ] [ 1 2 1 1<br />

AB + AC =<br />

3 4 1 −1<br />

[ ] 3 −1<br />

= +<br />

7 −1<br />

[ ] 7 4<br />

=<br />

17 10<br />

]<br />

+<br />

[ 4 5<br />

10 11<br />

[ 1 2<br />

3<br />

]<br />

4<br />

] [ ] 2 1<br />

1 2<br />

60

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