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Fundamentals of Matrix Algebra, 2011a

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B 4,3 =<br />

∣<br />

1 2 8<br />

−3 5 2<br />

−1 9 6<br />

∣<br />

!<br />

= ?<br />

3.3 The Determinant<br />

Again, we’re stuck. We won’t be able to fully compute C 4,3 ; all we know so far is that<br />

C 4,3 = (−1) 4+3 B 4,3 = (−1)B 4,3 .<br />

Once we learn how to compute determinates for matrices larger than 2 × 2 we can<br />

come back and finish this exercise. .<br />

In our previous example we ran into a bit <strong>of</strong> trouble. By our definion, in order<br />

to compute a minor <strong>of</strong> an n × n matrix we needed to compute the determinant <strong>of</strong> a<br />

(n − 1) × (n − 1) matrix. This was fine when we started with a 3 × 3 matrix, but when<br />

we got up to a 4 × 4 matrix (and larger) we run into trouble.<br />

We are almost ready to define the determinant for any square matrix; we need<br />

one last definion.<br />

.<br />

Ḋefinion 25<br />

C<strong>of</strong>actor Expansion<br />

Let A be an n × n matrix.<br />

.<br />

The c<strong>of</strong>actor expansion <strong>of</strong> A along the i th row is the sum<br />

a i,1 C i,1 + a i,2 C i,2 + · · · + a i,n C i,n .<br />

The c<strong>of</strong>actor expansion <strong>of</strong> A down the j th column is the sum<br />

a 1,j C 1,j + a 2,j C 2,j + · · · + a n,j C n,j .<br />

The notaon <strong>of</strong> this definion might be a lile inmidang, so let’s look at an example.<br />

. Example 70 .Let<br />

⎡<br />

A = ⎣ 1 2 3 ⎤<br />

4 5 6 ⎦ .<br />

7 8 9<br />

Find the c<strong>of</strong>actor expansions along the second row and down the first column.<br />

S<br />

the sum<br />

By the definion, the c<strong>of</strong>actor expansion along the second row is<br />

a 2,1 C 2,1 + a 2,2 C 2,2 + a 2,3 C 2,3 .<br />

(Be sure to compare the above line to the definion <strong>of</strong> c<strong>of</strong>actor expansion, and see<br />

how the “i” in the definion is replaced by “2” here.)<br />

139

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