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MYSTERIES OF THE EQUILATERAL TRIANGLE - HIKARI Ltd

MYSTERIES OF THE EQUILATERAL TRIANGLE - HIKARI Ltd

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36 Mathematical Properties<br />

Figure 2.12: Fermat Point<br />

connecting each vertex of the original triangle to the new vertex of the opposite<br />

equilateral triangle. These three segments are of equal length and intersect at<br />

the isogonic center where they are inclined at 60 ◦ to one another. At the<br />

isogonic center, each side of the original triangle subtends an angle of 120 ◦ .<br />

Also, the isogonic center lies at the common intersection of the circumcircles of<br />

the three equilateral triangles [322]. The algebraic sum of the distances from<br />

the isogonic center to the vertices of the triangle equals the length of the equal<br />

segments from the latter to the opposite vertices of the equilateral triangles<br />

[189].<br />

Property 13 (Largest Circumscribed Equilateral Triangle). If we connect<br />

the isogonic center of an arbitrary triangle with its vertices and draw lines<br />

through the latter perpendicular to the connectors then these lines intersect to<br />

form the largest equilateral triangle circumscribing the given triangle [189].<br />

This is the antipedal triangle of the isogonic center with respect to the given<br />

triangle.<br />

Property 14 (Napoleon’s Theorem). On each side of an arbitrary triangle,<br />

construct an equilateral triangle pointing outwards. The centers of these three<br />

triangles form an equilateral triangle [178] called the outer Napoleon triangle<br />

(Figure 2.13(a)).

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