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MYSTERIES OF THE EQUILATERAL TRIANGLE - HIKARI Ltd

MYSTERIES OF THE EQUILATERAL TRIANGLE - HIKARI Ltd

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54 Mathematical Properties<br />

Figure 2.34: Smallest Inscribed Triangle [57, 62]<br />

This radius is equal to s ·<br />

� 3 √ 3<br />

4π<br />

[161] so that the circular arc has length<br />

.673...s which is much shorter than either the .707...s length of the parallel<br />

bisector or the .866...s length of the altitude.<br />

Property 53 (Smallest Inscribed Triangle). The problem of finding the<br />

triangle of minimum perimeter inscribed in a given acute triangle [62] was<br />

posed by Giulio Fagnano and solved using calculus by his son Giovanni Fagnano<br />

in 1775 [224]. (An inscribed triangle being one with a vertex on each side of<br />

the given triangle.) The solution is given by the orthic/pedal triangle of the<br />

given acute triangle (Figure 2.34 left).<br />

Later, H. A. Schwarz provided a geometric proof using mirror reflections<br />

[57]. Call the process illustrated on the left of Figure 2.34 the pedal mapping.<br />

Then, the unique fixed point of the pedal mapping is the equilateral triangle<br />

[194]. That is, the equilateral triangle is the only triangle that maintains its<br />

form under the pedal mapping. Also, the equilateral triangle is the only triangle<br />

for which successive pedal iterates are all acute [205]. Finally, the maximal<br />

ratio of the perimeter of the pedal triangle to the perimeter of the given acute<br />

triangle is 1/2 and the unique maximizer is given by the equilateral triangle<br />

[158]. For a given equilateral triangle, the orthic/pedal triangle coincides with<br />

the medial triangle which is itself equilateral (Figure 2.34 right).<br />

Property 54 (Closed Light Paths [57]). The walls of an equilateral triangular<br />

room are mirrored. If a light beam emanates from the midpoint of a<br />

wall at an angle of 60 ◦ , it is reflected twice and returns to its point of origin<br />

by following a path along the pedal triangle (see Figure 2.34 right) of the room.<br />

If it originates from any other point along the boundary (exclusive of corners)<br />

at an angle of 60 ◦ , it is reflected five times and returns to its point of origin<br />

by following a path everywhere parallel to a wall (Figure 2.35) [57].

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