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L ′′ x 2(x, y, λ) = [L′ x (x, y, λ)]′ = ex+y + 2
L ′′ y 2(x, y, λ) = [L′ y (x, y, λ)]′ = ex+y + 2
L ′′ yx (x, y, λ) = ex+y − 2
e x+y + 2 e x+y − 2 1
e x+y − 2 e x+y + 2 1
1 1 0
4 ème étape : nature des points critique
A(1, 1, 3 − e 2 )
+
- +
Théorème :
Si dét(h) > 0 alors A max de L.
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