1666724786535_math analyse

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44
45 ∫ ln2 xxdx = ∫ 1 x . ln2 x dx12+1 ln3 x + c 1 3 ln3 x + c ∫ 1x lnx dx = ∫1xlnx dx = ln|ln x| + c ∫ x2x 2 +1 dx ∫ (x2 +1)−1dxx 2 +1 ∫ x2 +1− 1dxx 2 +1 x 2 +1 ∫ 1 − 1dx x 2 +1 = x − arctan x + c3. Primitives par partie :I = ∫ u. v ′ dxu ⟼ u′⟹ I = u. v′ ∫ u ′ . v dxv′ ⟼ vExemple :1. I = ∫ xe x dxu: x ⟼ u ′ = 1v ′ : e x ⟼ v = e xI = xe x − ∫ e x dx = xe x − e x + c
Page 1 and 2: Cours Math AnalyseAnnée 2020-2021U
Page 3 and 4: 3Donc x 2 +2 x-3 =0 ; a=1 ; b=2 ; c
Page 5 and 6: 51) Dérivée : Dérivées Usuelles
Page 7 and 8: 7Application 1 :Déterminer le doma
Page 9 and 10: 9II. Différentielle et valeur appr
Page 11 and 12: 116. ∆ f = f(x) − f(x 0 ) ≅ d
Page 13 and 14: 13 f ′ (x) = (2 − 6) . ( e2x+1
Page 15 and 16: 15Correction :1. [Ln(f(x))] ′ = f
Page 17 and 18: 17‣ f admet un maximum absolu (gl
Page 19 and 20: 19f"(x) = e x (2x + x 2 ) + (2 + 2x
Page 21 and 22: 21 Développements limités usuels
Page 23 and 24: 23 f(x) = ln(2) + x 2 − x28 + x32
Page 25 and 26: 25Chapitre 3 : Fonctions aplusieurs
Page 27 and 28: 27f ′ x (x, y) = (xy)′ .(y−2x
Page 29 and 30: 294. Relation d’Euler :x. f ′ x
Page 31 and 32: 31
Page 33 and 34: 33xtt
Page 35 and 36: 352.= 2y. e xf ′ x (x 0; y 0) = 0
Page 37 and 38: 37Nature des points: H(0;0)⟹ dét
Page 39 and 40: 39L ′ y (x, y, λ) = ex+y − 3
Page 41 and 42: 41 Si dét(h) < 0 alors A min de L.
Page 43: 43Application:Trouver les primitive
Page 47 and 48: 47f(x) = ∫ 1dx = ∫ 14+x 2 4+( x
Page 49 and 50: 49II. Calcul des sommes :∑+∞κ=

1666724786535_math analyse

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