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⎡⎢⎣1 0 0 02 1 0 0−0.5 l 32 1 01.5 l 42 l 43 1• III o blocco di eq.⎤⎥⎦⎡⎤ ⎡2 1 3 4⎢ 0 u 22 u 23 u 24⎥⎣ 0 0 u 33 u 34⎦ = ⎢⎣0 0 0 u 442 1 3 44 −1 2 1−1 1 8 33 1 4 1( II a riga di L) ·U = (II a riga di A),⎤⎥⎦u 2j := a 2j − l 21 · u 1jper j = 2, . . . , n[2 1 0 0]·U = [4 −1 2 1] 2+u 22 = −1, 6+u 23 = 2, 8+u 24 = 1⇒ u 22 = −3, u 23 = −4, u 24 = −7.

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