CDV34 Gas Fireplace - Continental Fireplaces

14
when (H ) > (V )
T T
Simple venting configurations
See graph to determine the required vertical rise V T for the
required horizontal run H T .
MAXIMUM
VERTICAL
RISE IN
FEET
V T
HORIZONTAL VENT RUN PLUS OFFSET IN FEET HT The shaded area within the lines represents acceptable
values for H and V .
T T
For vent configurations requiring more than two 90° elbow
(top exit) or one 90° elbow (rear exit), the following formulas
apply:
Formula 1: H < 3V T T
Formula 2: H + V < 40 feet
T T
Example 7:
W415-0345 / L / 03.05.09
BCDV34 / CDV34
90°
V 1
H 1
VERTICAL TERMINATION
FIGURE 17
BCDV33 / CDV33
90°
V 2
FIGURE 18
90°
H 2
V 3
90°
V1 V2 V3 VT H 1
H 2
HR HO =2 ft
=1 ft
=1.5 ft
= V + V + V = 2 + 1 + 1.5 = 4.5 ft
1 2 3
=6 ft
=2 ft
= H + H = 6 + 2 = 8 ft
1 2
= .03(four 90° elbows - 90°)
= .03(90 + 90 + 90 + 90 - 90) = 8.1 ft
H =H + H = 8 + 8.1 = 16.1 ft
T
R O
H + V = 16.1 + 4.5 = 20.6 ft
T T
Formula 1: H < 3V T T
3V = 3 x 4.5 = 13.5 ft
T
16.1 > 13.5
Since this formula is not met, this vent configuration is unacceptable.
Formula 2: H + V < 40 feet
T T
20.6 < 40
Since only formula 2 is met, this vent configuration is unacceptable
and a new fireplace location or vent configuration
will need to be established to satisfy both formulas.
Example 8:
V1 V2 VT H 1
H 2
H 3
HR HO H 1
90°
V 1
H 2
90°
45°
H 3
FIGURE 19
V 2
=1.5 ft
=5 ft
= V + V = 1.5 + 5 = 6.5 ft
1 2
=1 ft
=1 ft
=10.75 ft
= H + H + H = 1 + 1 + 10.75 = 12.75 ft
1 2 3
= .03(three 90° elbows + one 45° elbow - 90°)
= .03(90 + 90 + 90 + 45 - 90) = 6.75 ft
H =H + H = 12.75 + 6.75 = 19.5 ft
T
R O
H + V = 19.5 + 6.5 = 26 ft
T T
90°
Formula 1: H < 3V T T
3V = 3 x 6.5 = 19.5 ft
T
19.5 = 19.5
Formula 2: H + V < 40 feet
T T
26 < 40
Since both formulas are met, this vent configuration is acceptable.