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Syllabus Vector Differentiation - Velocity and Acceleration - Gradient ...

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Engineering Mathematics - II - <strong>Vector</strong> Calculus - 2007<br />

<br />

4 i 4 j<br />

2k<br />

<br />

36<br />

<br />

2<br />

3<br />

<br />

i <br />

2<br />

3<br />

1 <br />

j<br />

k<br />

3<br />

05. A particle moves so that its position vector is given by<br />

<br />

r cos t<br />

i<br />

sin t<br />

j,<br />

is<br />

a<br />

cons tan t<br />

show<br />

that<br />

<br />

i) velocity v<br />

is perpendicular to<br />

<br />

r<br />

ii) acceleration<br />

to the distance from the origin.<br />

<br />

a is directed towards the origin <strong>and</strong> has magnitude proportional<br />

<br />

iii) r x v is a cons tan t vector.<br />

Suggested answer:<br />

i)<br />

<br />

r cos t<br />

i sin t<br />

j<br />

<br />

d r<br />

dt<br />

<br />

<br />

sin t<br />

i cos t<br />

j v<br />

Now<br />

<br />

v . r 0<br />

<br />

v r<br />

ii)<br />

<br />

a <br />

<br />

d<br />

2<br />

r<br />

dt<br />

2<br />

<br />

<br />

<br />

2<br />

cos t<br />

i sin t<br />

j<br />

<br />

a <br />

2<br />

r<br />

<br />

| a | 2 <br />

| r |<br />

iii)<br />

<br />

r x v<br />

Page 40 of 72

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