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Syllabus Vector Differentiation - Velocity and Acceleration - Gradient ...

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Engineering Mathematics - II - <strong>Vector</strong> Calculus - 2007<br />

<br />

0 r<br />

n<br />

div( a x r )<br />

<br />

<br />

i j k<br />

a x r a1<br />

a2<br />

a3<br />

x y z<br />

<br />

i(a2z a3y) j(a1z a3x) k(a1y a2x)<br />

<br />

<br />

<br />

div( a x r ) (a2z<br />

a3y)<br />

(a3x<br />

a1z)<br />

(a1y<br />

a2x)<br />

x<br />

y<br />

z<br />

= 0 + 0 + 0<br />

= 0<br />

div(r<br />

n <br />

( a x r )) 0<br />

27. If<br />

<br />

a <strong>and</strong><br />

<br />

b<br />

are constant vectors, prove that<br />

<br />

i) div{( a x r ) b} a . b<br />

<br />

ii) div { a x( r x b )} 2( a . b )<br />

<br />

iii) div {( a x r )x(b x r )} [a,<br />

b , r ]<br />

Suggested answer:<br />

<br />

Let a a1<br />

i a2<br />

j<br />

a3<br />

k<br />

<br />

b b1<br />

i b2<br />

j<br />

b3<br />

k<br />

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