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C-32 Appendix C<br />
Setting 2x 4 x, we obtain 3x 4, and consequently, x 43. This is<br />
the required x-coordinate of the turning point. For the y-coordinate we have<br />
4 4<br />
512<br />
f 1 32 21 3214 4 32 2 . As you can verify, that works out to In summary, the<br />
4<br />
coordinates of the turning point are 1 3, 512<br />
27 .<br />
27 2.<br />
Third sample problem: According to Figure B, the graph of the polynomial<br />
function defined by g(x) x 2 (1 x) has a turning point in the first quadrant.<br />
Find the x-coordinate of that turning point. First, note that on the open interval<br />
0 x 1, each of the three factors x, x again, and 1 x is positive. However,<br />
as you can check, the sum of the three factors is not constant. We can work<br />
around this by writing<br />
x<br />
(x)(x)(1 x) 4 ca<br />
2 ba x<br />
b (1 x)d<br />
2<br />
Graphical Perspective<br />
1<br />
0<br />
Figure B<br />
g(x) x 2 (1 x)<br />
_1<br />
_1 0 1 2<br />
Now notice that the three factors in brackets do have a constant sum. For a<br />
x<br />
maximum then, we require that 2 1 x. Solving this last equation yields<br />
x 23, the required x-coordinate.<br />
Exercises<br />
1. (a) First, sketch a graph of the function f(x) x 2 (6 2x) using the standard<br />
techniques from Section 4.6. Then, use the ideas presented above<br />
to find the exact coordinates of the turning point in the first quadrant.<br />
(b) Follow part (a), but use g(x) x 2 (6 3x).<br />
2. An open-top box is to be constructed from a 16-inch square sheet of cardboard<br />
by cutting out congruent squares at each corner and then folding up the<br />
flaps. See the following figure. Express the volume of the box as a function<br />
of a single variable. Then find the maximum possible volume for the box.<br />
16 in.<br />
x<br />
x<br />
16 in.<br />
x