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Appendix C C-37<br />
PROJECT<br />
Coffee Temperature<br />
Suppose that a cup of hot coffee at a temperature of T 0 is set down to cool in a<br />
room where the temperature is kept at T 1 . Then the temperature of the coffee as<br />
it cools can be modeled by the function<br />
f(t) (T 0 T 1 )e kt T 1<br />
(1)<br />
Here, f(t) is the temperature of the coffee after t minutes; t 0 corresponds to<br />
the initial instant when the temperature of the hot coffee is T 0 ; and k is a (negative)<br />
constant that depends, among other factors, on the dimensions of the cup<br />
and the material from which it is constructed. [This model is derived in calculus.<br />
It is based on Newton’s law of cooling: The rate of change of temperature<br />
of a cooling object is proportional to the difference between the temperature of<br />
the object and the surrounding temperature. (Note: y is proportional to x means<br />
y kx for some constant k.)]<br />
After studying the following example, solve Problem A below by applying<br />
equation (1) and using the technique shown in the example. Then try your hand<br />
at Problem B. You won’t be able to complete Problem B using the techniques<br />
developed in this text up to now. In complete sentences, explain exactly at<br />
which point you get stuck. What would you have to know how to do to complete<br />
the solution? (In the next section we discuss logarithms, which will allow<br />
us to complete Problem B.) For now, use a graphing utility to obtain an approximate<br />
answer for Problem B.<br />
EXAMPLE<br />
Coffee Temperature Project<br />
Given that the graph of the function y ae kx passes through the points (0, 2)<br />
and (3, 5), find y when x 7.<br />
SOLUTION<br />
Substituting x 0 and y 2 in the given equation yields 2 ae 0 , and therefore<br />
a 2. Next, substituting x 3 and y 5 in the equation y 2e kx yields<br />
5 2e k(3) , or e 3k 2.5. This last equation can be rewritten (e k ) 3 2.5. Taking<br />
the cube root of both sides gives us<br />
e k 2.5 13<br />
(2)<br />
The original function can now be written as follows<br />
y 2e kx 2(e k ) x<br />
2(2.5 13 ) x<br />
using equation (2)