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Student Seminar: Classical and Quantum Integrable Systems

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is the bounded kinetic energy). According to the known theorem in topology, a<br />

two-dimensional compact orientable manifold admitting globally defined vector field<br />

is isomorphic to a torus. This is our Liouville torus 3 . According to the Liouville<br />

theorem motion on the torus will be characterized by two frequencies ω 1 <strong>and</strong> ω 2 . If<br />

their ratio is not a rational number then the body never returns to its original state<br />

of motion.<br />

Consider a rigid body rotation around a fixed point O <strong>and</strong> denote by K a coordinate<br />

system rotating with the body around O: in K the body is at rest. Every<br />

vector in K is carried to k by an operator B. By definition of the angular momentum<br />

we have<br />

M = q × m ˙q = m q × (ω × q) .<br />

Denote by J <strong>and</strong> by Ω the angular momentum <strong>and</strong> angular velocity in the moving<br />

frame K. We have<br />

J = m Q × (Ω × Q) .<br />

This defines a linear map A: K → K such that AΩ = J. This operator is symmetric:<br />

(AX, Y ) = (m Q × (X × Q), Y ) = m(Q × X, Q × Y )<br />

because the r.h.s. is symmetric function of X, Y . The operator A is called the inertia<br />

tensor. We see that taking X = Y = Ω we get<br />

E = T = 1 2 (AΩ, Ω) = 1 2 (J, Ω) = m 2 (Q × Ω, Q × Ω) = m 2 ˙Q 2 = m 2 ˙q2 .<br />

being a symmetric operator A is diagonalizable <strong>and</strong> it defines three mutually orthogonal<br />

characteristic directions. In the basis where A is diagonal the inertia operator<br />

<strong>and</strong> the kinetic energy take a very simple form<br />

J i = I i Ω i ,<br />

T = 1 3∑<br />

I i Ω 2 i .<br />

2<br />

The axes of this particular coordinate system are called the principle inertia axes.<br />

Problem. Rewrite expression for energy via the quantities of the stationary frame k.<br />

We have<br />

i=1<br />

E = 1 2 (AΩ, Ω) = 1 2 (J, Ω) = 1 2 (M, ω) = m 2 (q × (q × ω), ω) = m (q × ω, q × ω)<br />

2<br />

= 1 (ω<br />

2 m 2 q 2 − (ωq) 2) = 1 )<br />

2 ω iω j m<br />

(x 2 i δ ij − x i x j .<br />

} {{ }<br />

inertia tensor<br />

3 We cannot use the Liouville theorem to derive this result, because the integrals M i do not<br />

commute with each other <strong>and</strong>, therefore, the Frobenious theorem cannot be applied to deduce that<br />

the level set is a smooth manifold. Nevertheless we can identify the Liouville torus by different<br />

means.<br />

– 22 –

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