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Student Seminar: Classical and Quantum Integrable Systems

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4.2.2 Sine-Gordon cnoidal wave <strong>and</strong> soliton<br />

Consider the Sine-Gordon equation<br />

φ tt − φ xx + m2<br />

β<br />

sin βφ = 0 ,<br />

where we assume that the functions φ(x, t) <strong>and</strong> φ(x, t) + 2π/β are assumed to be<br />

equivalent. Make an ansatz<br />

φ(x, t) = φ(x − vt)<br />

which leads to<br />

This can be integrated once<br />

C = v2 − 1<br />

φ 2 x − m2<br />

2<br />

(v 2 − 1)φ xx + m2<br />

β<br />

β cos βφ = v2 − 1<br />

2 2<br />

sin βφ = 0 .<br />

φ 2 x + 2m2<br />

β 2<br />

βφ<br />

sin2<br />

2 − m2<br />

β . 2<br />

where C is an integration constant. This is nothing else as the conservation law of<br />

energy for the mathematical pendulum in the gravitational field of the Earth! We<br />

further bring equation to the form<br />

φ 2 x = 2 (C + m2<br />

v 2 − 1 β − 2m2<br />

2 β 2<br />

βφ sin2 2<br />

As in the case of the pendulum we make a substitution y = sin βφ<br />

2<br />

(<br />

C +<br />

m 2<br />

(y ′ ) 2 = m2<br />

(v 2 − 1) (1 − y2 )<br />

)<br />

β 2<br />

− y 2 .<br />

2m 2<br />

β 2<br />

)<br />

. (4.1)<br />

which gives<br />

This leads to solutions in terms of elliptic functions which are analogous to the cnoidal<br />

waves of the KdV equation. However, as we know the pendulum has three phases<br />

of motion: oscillatory (elliptic solution), rotatory (elliptic solution) <strong>and</strong> motion with<br />

an infinite period. The later solution is precisely the one that would correspond to<br />

the Sine-Gordon soliton we are interested in. Assuming v 2 < 1 we see 7 that such<br />

a solution would arise from (4.1) if we take C = − m2 . In this case equation (4.1)<br />

β 2<br />

reduces to<br />

2m<br />

φ x =<br />

β √ βφ<br />

sin<br />

1 − v2 2 .<br />

This can be integrated to 8<br />

4<br />

( m(x − vt −<br />

φ(x, t) = −ɛ 0<br />

β arctan exp x0 )<br />

)<br />

√ .<br />

1 − v<br />

2<br />

7 Restoring the speed of light c this condition for the velocity becomes v 2 < c 2 , i.e., the center<br />

of mass of the soliton cannot propagate faster than light.<br />

8 From the equation above we see that if φ(x, t) is a solution then −φ(x, t) is also a solution.<br />

– 45 –

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