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Student Seminar: Classical and Quantum Integrable Systems

Student Seminar: Classical and Quantum Integrable Systems

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The first problem is to find all possible Bethe quantum numbers (m 1 , m 2 ) for<br />

which Bethe equations have solutions. The allowed pairs (m 1 , m 2 ) are restricted to<br />

0 ≤ m 1 ≤ m 2 ≤ L − 1 .<br />

This is because switching m 1 <strong>and</strong> m 2 simply interchanges p 1 <strong>and</strong> p 2 <strong>and</strong> produces<br />

the same solution. There are 1 L(L + 1) pairs which meet this restriction but only<br />

2<br />

1L(L − 1) of them yield a solution of the Bethe equations. Some of these solutions<br />

2<br />

have real p 1 <strong>and</strong> p 2 , the others yield the complex conjugate momenta p 2 = p ∗ 1.<br />

The simplest solutions are the pairs for which one of the Bethe numbers is zero,<br />

e.g. m 1 = 0, m = m 2 = 0, 1, . . . , L − 1. For such a pair we have<br />

Lp 1 = θ(p 1 , p 2 ) , Lp 2 = 2πm + θ(p 2 , p 1 ) ,<br />

which is solved by p 1 = 0 <strong>and</strong> p 2 = 2πm.<br />

Indeed, for p L<br />

1 = 0 the phase shift vanishes:<br />

θ(0, p 2 ) = 0. These solutions have the dispersion relation<br />

E − E 0 = 2J sin 2 p 2 , p = p 2<br />

which is the same as the dispersion for the one-magnon states. These solutions are<br />

nothing else but su(2)-descendants of the solutions with M = 1.<br />

One can show that for M = 2 all solutions are divided into three distinct classes<br />

Descendents<br />

} {{ } , Scattering States , Bound<br />

} {{ }<br />

} {{ States }<br />

L<br />

L(L−5)<br />

L−3<br />

+3 2<br />

so that<br />

L(L − 5)<br />

L + + 3 + L − 3 = 1 L(L − 1)<br />

2<br />

2<br />

gives a complete solution space of the two-magnon problem.<br />

Pseudo−vacuum<br />

F<br />

L one−magnon states<br />

01<br />

01<br />

01<br />

01<br />

01<br />

01<br />

01 01<br />

01<br />

01 L(L−1)<br />

2<br />

two−magnon states<br />

0 0 1<br />

01<br />

01<br />

0<br />

0 1 0<br />

01<br />

1<br />

101 0 1<br />

1<br />

01 0<br />

01 01 01 01<br />

0 1<br />

1<br />

01<br />

1 01<br />

0 1<br />

– 66 –

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