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Real and Complex Analysis (Rudin)

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140 REAL AND COMPLEX ANALYSIS<br />

We shall now discuss these topics.<br />

7.8 Theorem Suppose J.L is a complex Borel measure on Rk, <strong>and</strong> J.L ~ m. Let f be<br />

the Radon-Nikodym derivative of J.L with respect to m. Then DJ.L = f a.e. Em],<br />

<strong>and</strong><br />

(1)<br />

for all Borel sets E c: Rk.<br />

In other words, the Radon-Nikodym derivative can also be obtained as a<br />

limit of the quotients Q, J.L.<br />

PROOF The Radon-Nikodym theorem asserts that (1) holds withfin place of<br />

DJ.L. At any Lebesgue point x off, it follows that<br />

f(x) = lim _1_ r f dm = lim J.L(B(x, r)) .<br />

,-0 m(B,) JB(X.,) ,-0 m(B(x, r))<br />

(2)<br />

Thus (DJ.L)(x) exists <strong>and</strong> equals f(x) at every Lebesgue point off, hence a.e.<br />

~]. M<br />

7.9 Nicely shrinking sets Suppose x e Rk. A sequence {Ei} of Borel sets in Rk is<br />

said to shrink to x nicely if there is a number IX > 0 with the following property:<br />

There is a sequence of balls B(x, ri), with lim ri = 0, such that Ei c: B(x, ri) <strong>and</strong><br />

m(Ei) :2= IX • m(B(x, ri)) (1)<br />

for i = 1,2,3, ....<br />

Note that it is not required that x e E i , nor even that x be in the closure of<br />

Ei. Condition (1) is a quantitative version of the requirement that each Ei must<br />

occupy a substantial portion of some spherical neighborhood of x. For example,<br />

a nested sequence of k-cells whose longest edge is at most 1,000 times as long as<br />

its shortest edge <strong>and</strong> whose diameter tends to 0 shrinks nicely. A nested sequence<br />

of rectangles (in R2) whose edges have lengths Iii <strong>and</strong> (1/0 2 does not shrink<br />

nicely.<br />

7.10 Theorem Associate to each x e Rk a sequence {Ei(X)} that shrinks to x<br />

nicely, <strong>and</strong> letfe IJ(Rk). Then<br />

f(x) = lim 1 r f dm<br />

i-oo m(Ei(X)) JEi(X)<br />

(1)<br />

at every Lebesgue point off, hence a.e. Em].

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