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Real and Complex Analysis (Rudin)

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HOLOMORPHIC FOURIER TRANSFORMS 373<br />

<strong>and</strong><br />

(3)<br />

Note: The function F we are looking for is to have the property thatf(x + iy) is<br />

the Fourier transform of F(t)e- yt (we regard y as a positive constant). Let us<br />

apply the inversion formula (whether or not this is correct does not matter; we<br />

are trying to motivate the proof that follows): The desired F should be of the<br />

form<br />

1 foo 1 f<br />

F(t) = eY • - f(x + iy)e-it" dx = - f(z)e-1tz: dz.<br />

21t _ 00 21t<br />

The last integral is over a horizontal line in n +, <strong>and</strong> if this argument is correct at<br />

all, the integral will not depend on the particular line we happen to choose. This<br />

suggests that the Cauchy theorem should be invoked.<br />

(4)<br />

PROOF Fix y, 0 < y < 00. For each !X > 0 let r", be the rectangular path with<br />

vertices at ± IX + i <strong>and</strong> ± IX + iy. By Cauchy's theorem<br />

r f(z)e - itz: dz = o.<br />

(5)<br />

Jr.<br />

We consider only real values of t. Let (p) be the integral off(z)e-1tz: over<br />

the straight line interval from P + i to P + iy (P real). Put I = [y, 1] if y < 1,<br />

1= [1, y] if 1 < y. Then<br />

Put<br />

I (P)12 = Ilf(p +iu)e-it(/I+iU) dul2 ~ llf(p + iuW du le2tu duo (6)<br />

A(P) = II f(P + iu) 12 duo<br />

Then (1) shows, by Fubini's theorem, that<br />

21t<br />

1 faO<br />

_ 00 A(P) dP ~ Cm(I).<br />

(7)<br />

(8)<br />

Hence there is a sequence {!Xj} such that !Xr-+ 00 <strong>and</strong><br />

By (6), this implies that<br />

A(!Xj) + A( -!Xj)--+ 0<br />

U--+ 00).<br />

asj--+ 00.<br />

(9)<br />

(10)

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