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Real and Complex Analysis (Rudin)

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156 REAL AND COMPLEX ANALYSIS<br />

If f satisfies the hypotheses of the theorem, so does -f; therefore (6)<br />

holds with -fin place off, <strong>and</strong> these two inequalities together give (1). IIII<br />

Differentiable Transformations<br />

7.22 Definitions Suppose V is an open set in Rk, T maps V into Rk, <strong>and</strong><br />

x E V. If there exists a linear operator A on Rk (i.e., a linear mapping of Rk<br />

into Rk, as in Definition 2.1) such that<br />

lim I T(x + h) - T(x) - Ah I = 0<br />

h .... O Ihl<br />

(where, of course, h E Rk), then we say that T is differentiable at x, <strong>and</strong> define<br />

(1)<br />

T'(x) = A. (2)<br />

The linear operator T'(x) is called the derivative of T at x. (One shows<br />

easily that there is at most one linear A that satisfies the preceding requirements;<br />

thus it is legitimate to talk about the derivative of T.) The term differential<br />

is also often used for T'(x}.<br />

The point of (1) is of course that the difference T(x + h) - T(x) is<br />

approximated by T'(x)h, a linear function of h.<br />

Since every real number ex gives rise to a linear operator on Rl (mapping<br />

h to exh), our definition of T'(x) coincides with the usual one when k = 1.<br />

When A: Rk_ Rk is linear, Theorem 2.20(e) shows that there is a number<br />

~(A) such that<br />

for all measurable sets E c Rk. Since<br />

m(A(E» = ~(A)m(E) (3)<br />

A'(x) = A (4)<br />

<strong>and</strong> since every differentiable transformation T can be locally approximated<br />

by a constant plus a linear transformation, one may conjecture that<br />

m(T(E» ,..., ~(T'(x»<br />

m(E)<br />

for suitable sets E that are close to x. This will be proved in Theorem 7.24,<br />

<strong>and</strong> furnishes the motivation for Theorem 7.26.<br />

Recall that ~(A) = I det A I was proved in Sec. 2.23. When T is differentiable<br />

at x, the determinant of T'(x) is called the Jacobian of T at x, <strong>and</strong> is<br />

denoted by J .,.(x). Thus<br />

~(T'(x» = I J .,.(x) I. (6)<br />

The following lemma seems geometrically obvious. Its proof depends on the<br />

Brouwer fixed point theorem. One can avoid the use of this theorem by imposing<br />

(5)

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