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Real and Complex Analysis (Rudin)

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198 REAL AND COMPLEX ANALYSIS<br />

where E(Z) -+ 0 as z -+ Zo <strong>and</strong> '1(w) -+ 0 as w -+ wo. Put w = f(z), <strong>and</strong> substitute<br />

(2) into (3): If z =F Zo,<br />

h(z) - h(zo) = [g'(f(zo» + '1(f(z))][f'(zo) + E(Z)]'<br />

Z - Zo<br />

(4)<br />

The differentiability of f forces f to be continuous at Zo. Hence (1) follows<br />

from (4).<br />

10.4 Examples For n = 0, 1,2, ... , zn is holomorphic in the whole plane, <strong>and</strong><br />

the same is true of every polynomial in z. One easily verifies directly that liz<br />

is holomorphic in {z: z =F OJ. Hence, taking g(w) = 1/w in the chain rule, we<br />

see that iffl <strong>and</strong>f2 are in H(O) <strong>and</strong> 0 0 is an open subset of 0 in whichf2 has<br />

no zero, thenfllf2 E H(Oo).<br />

Another example of a function which is holomorphic in the whole plane<br />

(such functions are called entire) is the exponential function defined in the<br />

Prologue. In fact, we saw there that exp is differentiable everywhere, in the<br />

sense of Definition 10.2, <strong>and</strong> that exp' (z) = exp (z) for every complex z.<br />

10.5 Power Series From the theory of power series we shall assume only one fact<br />

as known, namely, that to each power series .<br />

00<br />

L ciz - at (1)<br />

n=O<br />

there corresponds a number R E [0, 00] such that the series converges absolutely<br />

<strong>and</strong> uniformly in D(a; r), for every r < R, <strong>and</strong> diverges ifz ¢ D(a; R). The "radius<br />

of convergence" R is given by the root test:<br />

..!.. = lim sup len 11/n.<br />

R n"'oo<br />

Let us say that a functionfdefined in 0 is representable by power series in 0<br />

if to every disc D(a; r) c 0 there corresponds a series (1) which G:onverges to f(z)<br />

for all z E D(a; r).<br />

10.6 Theorem Iff is representable by power series in 0, then f E H(O) <strong>and</strong> f' is<br />

also representable by power series in O. Infact, if<br />

for z E D(a; r), then for these z we also have<br />

00<br />

f(z) = L ciz - a)n (1)<br />

n=O<br />

00<br />

f'(z) = L ncn(z - a)n - 1. (2)<br />

n=l<br />

(2)

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