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Real and Complex Analysis (Rudin)

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1S8 REAL AND COMPLEX ANALYSIS<br />

for all Z E Q <strong>and</strong> all € > O. If we fix Z E Q <strong>and</strong> then let € -<br />

desired result I I(z) I :$; 1.<br />

We now turn to the general case. Put<br />

g(z) = M(a)(b-Z)/(b-a)M(b)(z-a)/(b-a),<br />

0, we obtain the<br />

(7)<br />

where, for M > 0 <strong>and</strong> w complex, M W is defined by<br />

M W = exp (w log M),<br />

<strong>and</strong> log M is real. Then g is entire, g has no zero, 1/g is bounded in n,<br />

I g(a + iy) I = M(a),<br />

I g(b + iy) I = M(b),<br />

<strong>and</strong> hence Ilg satisfies our previous assumptions. Thus I fig I :$; 1 in Q, <strong>and</strong><br />

this gives (3). (See Exercise 7.)<br />

IIII<br />

12.9 Theorem Suppose<br />

Q={X+iY:IYI 0 so that IX < {J < 1. For € > 0, define<br />

For ZEn,<br />

h,(z) = exp { _€(ePZ + e- PZ)}.<br />

Re [ePZ + e- PZ] = (e PX + e- PX) cos {Jy ~ b(eP x + e-P1 (5)<br />

where b = cos ({JnI2) > 0, since I {J I < 1. Hence<br />

I h,(z) I :$; exp { -€b(ePX + e- PX)} < 1 (z En). (6)<br />

It follows that I fh,1 :$; 1 on aQ <strong>and</strong> that<br />

I I(z)h,(z) I :$; exp {Ae,*1 - €b(ePX + e-P1} (z E. n). (7)<br />

(4)

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