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Real and Complex Analysis (Rudin)

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376 REAL AND COMPLEX ANALYSIS<br />

cl>,,(w) = - LOao!(X)e- WX dx (Re w < 0). (9)<br />

cl>o <strong>and</strong> cl>" are holomorphic in the indicated half planes because of (2).<br />

The significance of the functions cl>/X to (4) lies in the easily verified relation<br />

L:.r.(X)e-itX dx = cl>o(€ + it) - cl>,,( -€ + it) (t real). (10)<br />

Hence we have to prove that the right side of (10) tends to 0 as €-+ 0, if t > A<br />

<strong>and</strong> ift < -A.<br />

We shall do this by showing that any two of our functions cl>/X agree in<br />

the intersection of their domains of definition, i.e., that they are analytic continuations<br />

of each other. Once this is done, we can replace cl>o <strong>and</strong> cl>" by cl>,,/2<br />

in (10) if t < -A, <strong>and</strong> by cl>-,,/2 if t> A, <strong>and</strong> it is then obvious that the<br />

difference tends to 0 as € -+ o.<br />

So suppose 0 < {J - ex < n. Put<br />

ex+{J<br />

Y=-2-'<br />

{J-ex<br />

" = cos -2- > o.<br />

(11)<br />

so that w E nIX n np as soon as I wi> AI". Consider the integral<br />

l!(z)e- W % dz<br />

over the circular arc r given by r(t) = reit, ex ::; t ::; {J. Since<br />

Re (- wz) = - I wi r cos (t - y)::; - I w I r",<br />

the absolute value of the integr<strong>and</strong> in (13) does not exceed<br />

C exp {(A - I wi ,,)r}.<br />

(12)<br />

(13)<br />

(14)<br />

If I wi> AI" it follows that (13) tends to 0 as r-+ 00.<br />

We now apply the Cauchy theorem. The integral of !(z)e- W % over the<br />

interval [0, reiP] is equal to the sum of (13) <strong>and</strong> the integral over [0, rei/X].<br />

Since (13) tends to 0 as r-+ 00, we conclude that cl>/X(w) = cl>p(w) if w = I w I e- iy<br />

<strong>and</strong> I wi> AI", <strong>and</strong> then Theorem 10.18 shows that cl>/X<br />

<strong>and</strong> cl>p coincide in<br />

the intersection of the half planes in which they were originally defined.<br />

This completes the proof.<br />

19.4 Remarks Each of the two preceding proofs depended on a typical application<br />

of Cauchy's theorem. In Theorem 19.2 we replaced integration over<br />

one horizontal line by integration over another to show that 19.2(15) was<br />

I I I I

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