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Real and Complex Analysis (Rudin)

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310 REAL AND COMPLEX ANALYSIS<br />

then n(r) is about 1t - 1 kr", SO that<br />

lim log n(r) = k.<br />

,-+00 log r<br />

(6)<br />

This shows that the estimate (4) cannot be improved.<br />

Blaschke Products<br />

Jensen's formula makes it possible to determine the precise conditions which the<br />

zeros of a nonconstant f E H OO must satisfy.<br />

15.21 Theorem If {cxn} is a sequence in V such that CXn =I- 0 <strong>and</strong><br />

if k is a nonnegative integer, <strong>and</strong> if<br />

00<br />

L (1 - I CXn I) < 00, (1)<br />

n=1<br />

(Z E V), (2)<br />

then B E H oo , <strong>and</strong> B has no zeros except at the points CXn (<strong>and</strong> at the origin, if<br />

k > 0).<br />

We call this function B a Blaschke product. Note that some of the CXn may be<br />

repeated, in which case B has multiple zeros at those points. Note also that each<br />

factor in (2) has absolute value 1 on T.<br />

The term "Blaschke product" will also be used if there are only finitely many<br />

factors, <strong>and</strong> even if there are none, in which case B(z) = 1.<br />

PROOF The nth term in the series<br />

t 1 - cxn~z '~I<br />

n=1 1 - CXnZ cxn<br />

is<br />

CXn + ~ CXn I Z 1 (1 - I CXn I) :::;; 1 + r (1 - I cxn I)<br />

1 (1 - CXn z)cxn 1 - r<br />

if I z I :::;; r. Hence Theorem 15.6 shows that B E H(V) <strong>and</strong> that B has only the<br />

prescribed zeros. Since each factor in (2) has absolute value less than 1 in V,<br />

it follows that I B(z) I < 1, <strong>and</strong> the proof is complete.<br />

IIII<br />

15.22 The preceding theorem shows that<br />

00<br />

L (1 ~ I cxn I) < 00 (1)<br />

n=1

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