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Intermediate Algebra – Student Workbook – Second Edition 2013

Intermediate Algebra – Student Workbook – Second Edition 2013

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Lesson 6b - Rational Exponents and Radical Functions<br />

Mini-Lesson<br />

To solve SIMPLE radical equations algebraically (also called symbolically):<br />

Isolate the radical part of the equation on one side and anything else on the other<br />

Sometimes you will have radicals on both sides. That is ok.<br />

Raise both sides of the equation to a power that will “undo” the radical (2 power to get<br />

rid of square root, 3 power to get rid of cubed root, etc…)<br />

Solve for x.<br />

Be sure x is part of the domain for the radical part of your equation by checking your<br />

result in the original.<br />

Check your work using the graphing method if possible.<br />

Problem 10<br />

WORKED EXAMPLE <strong>–</strong> SOLVE RADICAL EQUATIONS<br />

ALGEBRAICALLY<br />

Solve the equation 10 3x 4 algebraically.<br />

First, square both sides to remove the square root.<br />

<br />

10 3x<br />

4<br />

10 3x<br />

<br />

2<br />

4<br />

2<br />

10 3x<br />

16<br />

Next, isolate x.<br />

10 3x<br />

16<br />

3x<br />

6<br />

x 2<br />

VERY IMPORTANT! Check x = <strong>–</strong>2 in the original equation to be sure it works! Not all<br />

solutions obtained using the process above will check properly in your equation. If an x does not<br />

check, then it is not a solution.<br />

10 3( 2)<br />

4<br />

x = <strong>–</strong>2 is the solution to this equation.<br />

10 6 4<br />

16 4<br />

4 4<br />

Scottsdale Community College Page 272 <strong>Intermediate</strong> <strong>Algebra</strong>

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