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Intermediate Algebra – Student Workbook – Second Edition 2013

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Appendix A:<br />

You Try Answers<br />

You Try Problem 3<br />

a) 52000, .03, 1.03, 52000(1.03) t<br />

b) $60282.25<br />

c) 104000 = 52000(1.03) t , 23 years<br />

Lesson 3b<br />

You Try Problem 6<br />

a) 462,768, .014, .986, P(t)=462,768(0.986) t<br />

b) 245,372<br />

c) 231,384 = 462,768(0.986) t , t is approximately 49 years<br />

You Try Problem 7<br />

P(t) = 145(1.03) t<br />

V(t) = 314(0.035) t<br />

P(t) = 412(1.1324) t<br />

I(t) = 546(0.98) t<br />

A(t) = 3(0.78) t<br />

P(t) = 3061(3.05) t<br />

You Try Problem 9<br />

a) y = 82.9(.837) x<br />

b) 16.3%<br />

c) (20, 2.36)<br />

d) (6.10, 28) and show graph<br />

e) 41.45 = 82.9(0.837) x , half-life 3.9<br />

Lesson 4a<br />

You Try Problem 1<br />

1, 2, 3, 4<br />

You Try Problem 5 (be sure to include the “because” statements for each one)<br />

a) 6<br />

b) 0 because 5 0 = 1,<br />

c) -3<br />

d) Does not exist<br />

e) ½<br />

You Try Problem 6<br />

b) log 3<br />

81= 4<br />

c) 7 5 =16807<br />

Scottsdale Community College Page 287 <strong>Intermediate</strong> <strong>Algebra</strong>

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