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Cryptology - Unofficial St. Mary's College of California Web Site

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4.8. EXERCISES 69<br />

5. Here we work with Decimation Ciphers modulo 28, using 27 = .<br />

(a) Encipher no spaces allowed with key 19.<br />

(b) Decipher CUDAZ KOTQW A. The enciphering key was 17.<br />

(c) Decipher XDOMQM HKE Q JYBQM KT . The enciphering key was 11.<br />

(d) Decipher P WHO ENOWL MKI. The enciphering key was 13.<br />

6. Encipher the following words, using the given linear cipher modulo 26.<br />

(a) Geometry, 3m + 7.<br />

(b) Algebra, 11m + 19.<br />

(c) Trigonometry, 7m + 2.<br />

7. Decipher the following words. They were enciphered with a linear cipher,<br />

modulo 26.<br />

(a) VFQDY DMBMP O, key 5m + 20.<br />

(b) TKIAB CVFQ, key 23m + 4.<br />

(c) YVZGN YNX, key 19m + 8.<br />

(d) HGZGR HGRXH, key 25m + 1.<br />

8. What happens if we follow a linear cipher by another linear cipher<br />

9. In this problem we work as we did in Chapter 3 Exercise 8: the numbers<br />

0 to 9 stand for themselves in the plaintext, 10 is for spaces, 11 to 36<br />

represent the letters <strong>of</strong> the alphabet, and we work modulo 37.<br />

(a) Encipher 8 or 9 using a Caesar cipher with key 11.<br />

(b) Encipher 25 cents using a Decimation cipher with key 18.<br />

(c) Encipher Tea for 2 using a Linear Cipher with key 13m + 6.<br />

(d) Decipher NAA52 5I5NB 75I52 5NAA. It was enciphered with a Decimation<br />

cipher with key k = 19.<br />

(e) Decipher 9AIB ZE0AD ZAEJB A9D66 PL. It was enciphered with a<br />

Linear Cipher with key 15m + 9.<br />

(f) Decipher REHQD HMHTQ H7. It was enciphered with a Linear Cipher<br />

with key 8m + 12.<br />

(g) Decipher A0L6O ISS. It was enciphered with a Linear Cipher with<br />

key 16m + 7.<br />

(h) Decipher 5UHUE XUKEL U5UH. It was enciphered with a Linear Cipher<br />

with key 31m + 17.<br />

(i) Decipher L2 83 3 T20 JIQ. It was enciphered with a Linear Cipher<br />

with key 13m + 20.

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