Answers to Quick Quizzes, Odd-Numbered Conceptual Questions and Problems A.2315. If an external battery is acting to increase the currentin the inductor, an emf is induced in a direction tooppose the increase of current. Likewise, if we attempt toreduce the current in the inductor, the emf that is set uptends to support the current. Thus, the induced emfalways acts to oppose the change occurring in the circuit,or it acts in the “back” direction to the change.17. (a) clockwise (b) The net force exerted on the bar must bezero because it moves at constant speed. The componentof the gravitational force down the incline is balanced by acomponent of the magnetic force up the incline.19. from left to rightCONCEPTUAL QUESTIONS1. For best reception, the length of the antenna should be parallelto the orientation of the oscillating electric field. Be-PROBLEMS1. 5.9 10 2 T m 23. 7.71 10 1 T m 25. (a) B,net 0 (b) 07. (a) 3.1 10 3 T m 2 (b) B,net 09. 0.18 T11. 94 mV13. 2.7 T/s15. (a) 4.0 10 6 T m 2 (b) 18 V17. 10.2 V19. 0.763 V21. (a) toward the east (b) 4.58 10 4 V23. (a) from left to right (b) from right to left25. (a) F N 2 B 2 w 2 v/R to the left (b) 0(c) F N 2 B 2 w 2 v/R to the left27. into the page29. (a) from right to left (b) from right to left (c) from leftto right (d) from left to right31. 1.9 10 11 V33. (a) 18.1 V (b) 035. (a) 60 V (b) 57 V (c) 0.13 s37. 20 mV39. (a) 2.0 mH (b) 38 A/s43. 12 mH45. 1.92 47. 0.140 J49. (a) 18 J (b) 7.2 J51. negative (V a V b )53. (a) 20.0 ms (b) 37.9 V (c) 1.52 mV (d) 51.8 mA55. 1.20 C57. (a) 0.500 A (b) 2.00 W (c) 2.00 W59. 115 kV61. (a) 0.157 mV (end B is positive) (b) 5.89 mV (end A ispositive)63. (a) 9.00 A (b) 10.8 N (c) b is at the higher potential(d) No65. v t mgRB 2 2Chapter 21ANSWERS TO QUICK QUIZZES1. (c)2. (b)3. (b)4. (b), (c)5. (b), (d)cause of atmospheric variations and reflections of the wavebefore it arrives at your location, the orientation of this fieldmay be in different directions for different stations.3. The primary coil of the transformer is an inductor. Whenan AC voltage is applied, the back emf due to the inductancewill limit the current in the coil. If DC voltage is applied,there is no back emf, and the current can rise to ahigher value. It is possible that this increased current willdeliver so much energy to the resistance in the coil that itstemperature rises to the point at which insulation on thewire can burn.5. An antenna that is a conducting line responds to the electricfield of the electromagnetic wave—the oscillatingelectric field causes an electric force on electrons in thewire along its length. The movement of electrons alongthe wire is detected as a current by the radio and is amplified.Thus, a line antenna must have the same orientationas the broadcast antenna. A loop antenna responds to themagnetic field in the radio wave. The varying magneticfield induces a varying current in the loop (by Faraday’slaw), and this signal is amplified. The loop should be inthe vertical plane containing the line of sight to thebroadcast antenna, so the magnetic field lines go throughthe area of the loop.7. The flashing of the light according to Morse code is adrastic amplitude modulation—the amplitude is changingfrom a maximum to zero. In this sense, it is similar tothe on-and-off binary code used in computers and compactdisks. The carrier frequency is that of the light, onthe order of 10 14 HZ. The frequency of the signaldepends on the skill of the signal operator, but it is on theorder of a single hertz, as the light is flashed on and off.The broadcasting antenna for this modulated signal is thefilament of the lightbulb in the signal source. The receivingantenna is the eye.9. The sail should be as reflective as possible, so that themaximum momentum is transferred to the sail from thereflection of sunlight.11. Suppose the extraterrestrial looks around your kitchen.Lightbulbs and the toaster glow brightly in the infrared.Somewhat fainter are the back of the refrigerator and theback of the television set, while the television screen isdark. The pipes under the sink show the same weak glowas the walls, until you turn on the faucets. Then the pipeon the right gets darker and that on the left develops agleam that quickly runs up along its length. The food onthe plates shines, as does human skin, the same color forall races. Clothing is dark as a rule, but your seat and thechair seat glow alike after you stand up. Your face appearslit from within, like a jack-o’-lantern; your nostrils and theopenings of your ear canals are bright; brighter still arethe pupils of your eyes.13. Radio waves move at the speed of light. They can travelaround the curved surface of the Earth, bouncing betweenthe ground and the ionosphere, which has an altitude thatis small compared with the radius of the Earth. Thedistance across the lower 48 states is approximately5 000 km, requiring a travel time that is equal to (5 10 6 m)/(3 10 8 m/s) 10 2 s. Likewise, radio wavestake only 0.07 s to travel halfway around the Earth. Inother words, a speech can be heard on the other side ofthe world (in the form of radio waves) before it is heard atthe back of the room (in the form of sound waves).
A.24 Answers to Quick Quizzes, Odd-Numbered Conceptual Questions and Problems15. No. The wire will emit electromagnetic waves only if thecurrent varies in time. The radiation is the result of acceleratingcharges, which can occur only when the current isnot constant.17. The resonance frequency is determined by the inductanceand the capacitance in the circuit. If both L and C are doubled,the resonance frequency is reduced by a factor of two.19. It is far more economical to transmit power at a highvoltage than at a low voltage because the I 2 R loss on thetransmission line is significantly lower at high voltage.Transmitting power at high voltage permits the use ofstep-down transformers to make “low” voltages and highcurrents available to the end user.21. No. A voltage is induced in the secondary coil only if theflux through the core changes with time.PROBLEMS1. (a) 141 V (b) 20.0 A (c) 28.3 A (d) 2.00 kW3. 70.7 V, 2.95 A5. 6.76 W9. 4.0 10 2 Hz11. 17 F15. 3.14 A17. 0.450 T m 219. (a) 0.361 A (b) 18.1 V (c) 23.9 V (d) 53.0°21. (a) 1.4 k (b) 0.10 A (c) 51° (d) voltage leads current23. (a) 89.6 V (b) 108 V25. 1.88 V27. (a) 103 V (b) 150 V (c) 127 V (d) 23.6 V29. (a) 208 (b) 40.0 (c) 0.541 H31. (a) 1.8 10 2 (b) 0.71 H33. 2.29 H35. C min 4.9 nF, C max 51 nF37. 0.242 J39. 0.18% is lost41. (a) 1.1 10 3 kW (b) 3.1 10 2 A (c) 8.3 10 3 A43. 1 000 km; there will always be better use for tax money.45. f red 4.55 10 14 Hz, f IR 3.19 10 14 Hz,E max,f /E max,i 0.5747. 2.94 10 8 m/s49. E max 1.01 10 3 V/m, B max 3.35 10 6 T51. (a) 188 m to 556 m (b) 2.78 m to 3.4 m53. 5.2 10 13 Hz, 5.8 m55. 4.299 999 84 10 14 Hz; 1.6 10 7 Hz(the frequency decreases)57. 99.6 mH59. 1.7 cents61. (a) resistor and inductor (b) R 10 , L 30 mH63. (a) 6.7 10 16 T (b) 5.3 10 17 W/m 2(c) 1.7 10 14 W65. (a) 0.536 N (b) 8.93 10 5 m/s 2 (c) 33.9 days67. 4.47 10 9 JChapter 22QUICK QUIZZES1. (a)2. Beams 2 and 4 are reflected; beams 3 and 5 are refracted.3. (b)4. (c)CONCEPTUAL QUESTIONS1. Sound radiated upward at an acute angle with the horizontalis bent back toward Earth by refraction. This meansthat the sound can reach the listener by this path as wellas by a direct path. Thus, the sound is louder.3. The color will not change, for two reasons. First, despitethe popular statement that color depends on wavelength,it actually depends on the frequency of the light, whichdoes not change under water. Second, when the light entersthe eye, it travels through the fluid within. Thus, evenif color did depend on wavelength, the important wavelengthis that of the light in the ocular fluid, which doesnot depend on the medium through which the light traveledto reach the eye.5. (a) Away from the normal (b) increases (c) remains thesame7. No, the information in the catalog is incorrect. The indexof refraction is given by n c/v, where c is the speed oflight in a vacuum and v is the speed of light in the material.Because light travels faster in a vacuum than in anyother material, it is impossible for the index of refractionof any material to have a value less than 1.9. There is no dependence of the angle of reflection on wavelength,because the light does not enter deeply into thematerial during reflection—it reflects from the surface.11. On the one hand, a ball covered with mirrors sparkles byreflecting light from its surface. On the other hand, afaceted diamond lets in light at the top, reflects it by totalinternal reflection in the bottom half, and sends the lightout through the top again. Because of its high index ofrefraction, the critical angle for diamond in air for totalinternal reflection, namely c sin 1 (n air /n diamond ), issmall. Thus, light rays enter through a large area and exitthrough a very small area with a much higher intensity.When a diamond is immersed in carbon disulfide, thecritical angle is increased to c sin 1 (n carbon disulfide /n diamond ). As a result, the light is emitted from the diamondover a larger area and appears less intense.13. The index of refraction of water is 1.333, quite differentfrom that of air, which has an index of refraction of about 1.The boundary between the air and water is therefore easy todetect, because of the differing diffraction effects above andbelow the boundary. (Try looking at a glass half full ofwater.) The index of refraction of liquid helium, however,happens to be much closer to that of air. Consequently,the defractive differences above and below the helium-airboundary are harder to see.15. The diamond acts like a prism, dispersing the light into itsspectral components. Different colors are observed as aconsequence of the manner in which the index of refractionvaries with the wavelength.17. Light travels through a vacuum at a speed of 3 10 8 m/s.Thus, an image we see from a distant star or galaxy musthave been generated some time ago. For example, thestar Altair is 16 lightyears away; if we look at an image ofAltair today, we know only what Altair looked like 16 yearsago. This may not initially seem significant; however,astronomers who look at other galaxies can get an idea ofwhat galaxies looked like when they were much younger.Thus, it does make sense to speak of “looking backward intime.”PROBLEMS1. 3.00 10 8 m/s3. 114 rad/s for a maximum intensity of returning light5. (b) 3.000 10 8 m/s
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Color-enhanced scanning electronmic
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876 Chapter 27 Quantum PhysicsSolve
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27.3 X-Rays 881even when black card
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27.5 The Compton Effect 885Exercise
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Problems 897The probability per uni
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Problems 89917. When light of wavel
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“Neon lights,” commonly used in
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28.3 Th Bohr Theory of Hydrogen 909
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28.12 Lasers and Holography 923is u
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28.13 Energy Bands in Solids 927Ene
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29.2 Binding Energy 943130120110100
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29.3 Radioactivity 947INTERACTIVE E
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Summary 965Photo Researchers, Inc./
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Problems 967CONCEPTUAL QUESTIONS1.
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Problems 96924. A building has beco
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Problems 97157. A by-product of som
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30.1 Nuclear Fission 975Applying Ph
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30.2 Nuclear Reactors 977Courtesy o
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30.2 Nuclear Reactors 979events in
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