Bukhovtsev-et-al-Problems-in-Elementary-Physics

MECHANICS 231
N
A
Fig. 951
T
With the given value of a, it will be the smaller, the greater is R.
Hence, the rod will fall faster if it is placed on end B.
188. According to Newton's second law, moolR =mg cos a,-N, where N Is
the force which the deformed rod acts on the sphere with.
The deformation of the rod will disappear when the rod no longer presses
on the floor, and N=O. As shown in Problem 187, 0=2 V~ sin ; ·
Upon inserting this value of co in the equation of motion, we find that
cos tI= ~ . Hence, tI=48°10'.
For the rod not to slip, the condition N sin a ~ 5 , the rod will not slip until N is zero, l.e., until tI';;;;
2
arc cos ~ , the equation m0 1 R=mg cos tI- N will give us
N