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Bukhovtsev-et-al-Problems-in-Elementary-Physics

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240 ANSWERS AND SOLUTIONS<br />

The closer the sections of the rod are to the axis of rotation, the more<br />

wi11 they be str<strong>et</strong>ched.<br />

204. In the read<strong>in</strong>g system that is stationary with respect to the axis, the<br />

force of tension of the rod does not perform any work, s<strong>in</strong>ce this force constantly<br />

rema<strong>in</strong>s 'perpendicular to the velocity of the b<strong>al</strong>l. In the mov<strong>in</strong>g system<br />

this force performs work other than zero, and this changes the k<strong>in</strong><strong>et</strong>ic energy<br />

of the b<strong>al</strong>l.<br />

205. Section AB of the hoop with a mass m at the highest po<strong>in</strong>t has an<br />

energy of mg 2R+m ~V)2. Dur<strong>in</strong>g motion the k<strong>in</strong><strong>et</strong>ic and potenti<strong>al</strong> energies<br />

of section AB beg<strong>in</strong> to decrease ow<strong>in</strong>g to the work of the forces of the elastic<br />

deformation of the hoop whose resultant produces a centrip<strong>et</strong><strong>al</strong> force <strong>al</strong>ways<br />

directed towards the centre. The velocity of section AB forms an obtuse angle a<br />

with the force F (Fig. 366). For this reason the work of the force W 1=F!1S cos a<br />

is negative, and, consequently, the energy of the section with the mass m<br />

dim<strong>in</strong>ishes.<br />

After section AB passes through the lowermost position, it is easy to see<br />

that the work of the force F becomes positive and the energy of section AB<br />

will grow.<br />

206. L<strong>et</strong> us draw a tangent to the <strong>in</strong>ner circumference of the spool (Fig. 367)<br />

from po<strong>in</strong>t A, which is the <strong>in</strong>stantaneous axis of rotation (see Problem 173).<br />

If the directions of the thread and the<br />

tangent AC co<strong>in</strong>cide, the moment<br />

of the forces that rotate the spool around the <strong>in</strong>stantaneous axis will be zero.<br />

Therefore, if the spool is at rest, it will not rotate around the <strong>in</strong>stantaneous<br />

axis and, consequently, it will not move translation<strong>al</strong>ly.<br />

The angle a at which the motion of the spool is reversed can be found from<br />

triangle AOB; namely, s<strong>in</strong> a = ; . If the thread is <strong>in</strong>cl<strong>in</strong>ed more than a,<br />

the spool will roll to the right, If a Is sm<strong>al</strong>ler it will move to the left on<br />

condition that it does not slip. If the tension of the thread T satisfies the<br />

condition Tr ez.iR, where f is the force of friction, the spool will rema<strong>in</strong> <strong>in</strong><br />

place. Otherwise, when s<strong>in</strong> a= ~ it will beg<strong>in</strong> to rotate counterclockwise<br />

around po<strong>in</strong>t o.<br />

207. Break the hoop <strong>in</strong>to equ<strong>al</strong> sm<strong>al</strong>l sections each with a mass of L\m.<br />

Consider two symm<strong>et</strong>ric<strong>al</strong> sections (relative to the centre). All the particles of<br />

the hoop simultaneously participate <strong>in</strong> translation<strong>al</strong> motion with the velocity<br />

Fig. 366 Fig. 367

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